(Hydrogen in mathematics lab of Sikande Aqeel)
PREPARING OF COMPLEX HYDRIDES (12/7/2015)
The complex hydrides prepare from reaction of Alkaline metals and try-halide
LiBH4 + 2H2O ---------------- LiBO2 + 4H2
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Lithium Meta Bromide
LiBH4 + 2H2O = 7 + 5 + 11 + 37 = 49
A = for example
Lithium-Boron-hydrides,
One electron or line = 0.008 photon
Metals Ratio = 50
LiBH4 + 2H2O = 60 m/g
LiBH4 + 2H2O = 60 M * 0.016 = 0.96
= 0.96 + 0.04 = 1
= 1 * 50 ratio = 50
= 50 M = LiBO2 = Lithium Meta Bromide
About lines = (0.008)2
Lines = 0.016
Lines = 0.016 / 0.008 = 2
= 2 + 8 = 10
= 10 M = (4H2)