ALKANES
(The electrons shells in mathematics lab of Sikander Aqeel)
The hydrogen mass is 1.25, when 1.25 / 1.25 = 1 proton value rise up, which of one electron into the k, shell with 0.5 cross-proton value,
About k, Shall,
The k shell is first orbit of atom for electrons, Why k shell always depends on 2 electron, because 2 electrons division power is equal to cross-proton of atom, such as Oxygen = 16 / 1.25 = 12.8 / 2k shell = 6.4 Cross-proton of oxygen,
We shall invent here the binding energy of atom and orbital velocity of electrons, for understand value and binding power of atom, such as H2O is strong acid than the all acids,
1 = orbital velocity of electron
2 = binding energy of atom,
Binding energy of Atom,
The binding energy of hydrogen is 0.5 where L shell is empty, the hydrogen binding energy is strong than the oxygen, and the binding energy of atom produces the orbital velocity of electrons, and this both system makes value of compound,
Orbital Energy of Electrons,
The orbital energy will be count in second number, because the different orbital velocities produce different compounds,
Hydrogen = 1.25 / 1.25 = 1 / 2k = 0.5 Cross-proton - 0.5 binding energy = 0L = 1 proton
Carbon = 12 / 1.25 = 9.6 / 2k = 4.8 Cross-proton – 0.8 binding energy = 4L = 6 proton
Nitrogen = 14 / 1.25 = 11.2 / 2k = 5.6 Cross proton – 0.6 binding energy = 5L = 7 proton
Oxygen = 16 / 1.25 = 19.5 / 2k = 9.5 Cross-proton – 0.4 binding energy = 6L = 8 proton
Iron = 56 / 1.25 = 44.8 / 2k = 22.4 Cross-proton – 8L = 14.4 – 14M = 0.4 + 1.6 binding energy = 2N
COMPOUND OF WATER
Water = H2O
One Oxygen = 0.4 binding energy
Two Hydrogen = 0.5 + 0.5 = 1 binding energy
______________
1.4 binding energy of H2O
Binding energy of water = 1.4 * 2.5 (H2) = 3.5
= 3.5 * 5.28 V = 18.48 or
= 18.5 mole H2O = water
Orbital velocity of shell in compound = 5.28 ms-1 velocity
1 = water orbital velocity of electron = 5.28 ms-1 velocity
2 = binding energy of water = 1.4,
As a prove
Water electron velocity = 5.28 * 9.50 cm = 528
= 528 / 60 sec = 8.8
= 8.8 – 0.8 = 8 proton of one oxygen atom
= 8.8 – 0.8 = 8 L shell
= 0.8 * 2.5 = 2 proton of two hydrogen atom,
= 0.8 / 2.5 = 0.32 * 50 ratio = 16 oxygen
So water electrons velocity = 5.28 m/sec
Orbit of electron shells of water = 5.28 m/sec
Quantity of Velocity
Water electron velocity = 5.28 / 0.008 photon = 660
= 660 / 60 sec = 11
= 11 + 7.4 cross neutron of water = 18.4
= 18.5 = water is always water = strong compound on planet
Water = 18.5 M / 1.25 = 14.8 / 2k = 7.4 Cross-proton = 2K shell
Water = 7.4 / 1.25 = 9.52 / 8L = 0.74 Cross-proton = 8L shell
___________ +
9.5 protons or two H electrons and eight O electrons
Because last large amount = 0.74 * 50 ratio = 37 M 2H2O, strong compound on planet
Water Orbital Value by Mathematics’
Water K shell = 2 electrons
Water L shell = 8 electrons
Oxygen = 16 / 1.25 = 19.5 / 2k = 9.5 Cross-proton – 0.4 binding energy = 6L = 8 proton
Hydrogen = 1.25 / 1.25 = 1 / 2k = 0.5 Cross-proton - 0.5 binding energy = 0L = 1 proton
Water = H2O
1 Oxygen = 0.4 binding energy
2 Hydrogen = 1 binding energy
______________
= 1.4 binding energy of Neo-Pentyl
Binding energy of Water = 1.4 * 2.5 (H2) = 3.5
= 3.5 * 5.28 k shall = 18.48
= 18.5 mole = Water
O1
Binding energy of Water = 1.4 * 16 (O1) = 22.4
= 22.4 - 3.9 (H3) = 18.5
= 18.5 M water
H3
Binding energy of Water = 1.4 * 3.9 (H3) = 5.46
= 5.46 – 2.96 H = 2.5
= 2.5 hydrogen of water
Water = H2O
------------------------------------------------------------------------------------------------------------------
RADICAL ALKANES (12/7/2015)
Hydrogen = 1.25 / 1.25 = 1 / 2k = 0.5 Cross-proton - 0.5 binding energy = 0L = 1 proton
Carbon = 12 / 1.25 = 9.6 / 2k = 4.8 Cross-proton – 0.8 binding energy = 4L = 6 proton
CH3
|
Neo-Pentyl = CH3 C – CH2 –
|
CH3
5 Carbon = 4 binding energy
11 Hydrogen = 5.5 binding energy
______________
= 9.5 binding energy of Neo-Pentyl
Binding energy of Neo-Pentyl = 9.5 * 2.5 (H2) = 23.75
= 23.75 * 3.105 (4sp3) k shall = 73.74
= 73.75 mole = Neo-Pentyl
= k shall = H3
CH3
|
Neo-Pentyl = CH3 C – CH2 –
|
CH3
CH3
Binding energy of Neo-Pentyl = 9.5 * 15.75 (CH3) = 149.625
= 149.625 / 12.5 H8 = 11.97
= 11.97 + 0.03 = 12 mole = C of second carbon atom
C
Binding energy of Neo-Pentyl = 9.5 * 12 (C) = 114
= 114 / 8 H = 14.25
= 14.25 + 0.25 = 14.5 mole = CH2 of third Carbenes
CH2
Binding energy of Neo-Pentyl = 9.5 * 14.5 (CH2) = 137.75
= 137.75 / 9 H = 15.30
= 15.30 + 0.45 = 15.75 mole = CH3 fourth upper Methyl
CH3
Binding energy of Neo-Pentyl = 9.5 * 15.75 (CH3) = 151.2
= 151.2 / 9.6 H = 15.75
= 15.75 + 0.0 = 15.75 mole = CH3 fifth lower Methyl
CH3
|
Neo-Pentyl = CH3 C – CH2 –
|
CH3
Total Hydrogen = 9.6 + 9 + 8 + 12.5 = 39.1 * 1.886 Heavy hydrogen = 73.75 Neo-Pentyl
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