(Bio Algebra of living organisms)
(Mathematical Lab of Sikander Aqeel)
CHAPTER 3 PROTEINS
Proteins = Clay
(1/28/2016)
The Size of Proteins Molecules
The molecular weight of proteins can be determined by means of various physical-chemical methods, some characteristic values, most range from about 12,000 to 1,000,000 or more, it is not possible even among proteins having the same type of function, and different enzymes, for example have molecular weight that very over a wide range,
we can calculate the approximate number of amino acid residues in a sample protein containing on prosthetic group by dividing its molecular weight by 120,
The average molecular weight of 20 different amino acids in proteins is about 138,
But since a molecule of water [mol wt 18.0 is removed to create each Peptide bond,
The average amino acid residue weight about 120, also gives the approximate number of amino acids residues for some proteins of different size and function,
Ribonuclease, Cytochrome c, and myoglobin, which are among the best known small proteins contain between 100 and 155 amino acids residues,
A = for example
= a2 + b2 = c2
Molecular weight residues No, of chain
(Bovine Pancreas) ----------- 22600 ------------ 241 -------------- 3 ------
Renitol = C20H29OH = 293.5 m/g
Histidine = C6H9N3O2 = 157.25 m/g
Isoleucine = C6H13NO2 = 134.25 m/g
Adenine = C5H5N5 = 135.13 m/g
Ribo-dsugar = C5H12O5 = 76.25 m/g
phosphate ion = HPO4 = 96.25 m/g
Alpha cells = 4(CH2OH) = 127 m/g
Beta cells = 4(CH2OH) = 127 m/g
Water = 2H2O = 37 m/g
Total chemical = 1183.63 m/g
Molecule of water = 18.0 mol
a2 + b2 = c2
a = Total chemical = 1183.63 m/g
b = Molecule of water = 18.0 mol
= a2 + b2 = c2
= a2 + b2 = c2 = Total chemical + water = c2
= a2 + b2 = c2 = a1183.63 mm + b18.0 mm = c2
= a1183.63 mm + b18.0 mm = c2
= a1400979.9769 + b324 = c2
= a + b = 1401303.9769 = c2
= a + b = 1401303.9769 / 1183 = 1183
= c = 1183 slope / 6.0784 more amino acids = 241 residues
= c = 1183 slope / 4.9087 more amino acids = 241 residues
= 241 * 1 No, of chain = 241 complete residues
Small proteins contain between = 100 and 155
Small proteins contain between = 94 * 241 complete residues = 22654
= 22654 + 54 = 22600
= 22600 Molecular weight Bovine Pancreas
Molecular weight residues No, of chain
(Bovine Pancreas) ----------- 22600 ------------ 241 -------------- 3 ------
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
r = Total chemical = 1183.63 m/g
r = Molecule of water = 18.0 mol
As amount Rate Time Glycogen
n = 45.375 COOH r + 1183.63 60 minute 60(r + 1183.63)
Lysozyme (egg white)
60r + 60(r + 1183.63) = 142035.6
60r + 60 + 71017.8 = 142035.6
120r + 71017.8 = 142035.6
120r + 71017.8 + 142035.6= 142035.6- 71017.8
120r = 71017.8
120r = 71017.8
----------- = -------------
120 = 120
r = 591.815
r = 591.815 - 249.565, [7.86(CH2OH)] = 342.25
r = 342.25 / 18.5 = 18.5
r = 18.5 - 0.5 = 18.0 mol water removed to create each peptide chain
Molecular weight residues No, of chain
(Bovine Pancreas) ----------- 22600 ------------ 241 -------------- 3 ------
Always remember my words,
Enzymes = Oxygen
Bacteria = Nitrogen
Virus = Carbon +
-----------------
= life by air, fire clay, and water,
And hydrogen is a partner of these three elements,
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