BIO ALGEBRA OF LIVING ORGANISMS

(Bio Mathematical Lab of Sikander Aqeel) 

CHAPTER 3 PROTEINS  

Proteins  

(2/29/2016) 

Amino Acid Sequence of Polypeptide Chain: 

Perhaps you have been read several method to identify the carboxyl-terminal residue, in one the terminal carboxyl of the polypeptide is reduce to a hydroxyl group, If the polypeptide chain is that completely hydrolyzed, the hydrolyzed will contain one molecule of an a-amino alcohol corresponding to the original carboxyl-terminal amino acids, 

Peptide = C7H8N2O4 = 84 + 10 + 28 + 64 = 186 mole 

a-amino acid = CH3CH(NH2)COOH = C3H7N1O2 = 36 + 8.75 + 14 + 32 = 90.75 mole

For example 

  = a2 / b2 = c2 

  = a2 = Peptide and b2 = a-amino acid = c2 

  = a2 = 186 and b2 = 90.75 = c2 

  = a186 / b90.75 = c2 

  = 34596 / 8235.5625 = c2 

  = a / b = 4.20 = c2 

  = a / b = 4.20 

  = a / b = 4.20 * 12 (C) = 50.4 

  = a / b = 50.4 – 6.4 hydrolyzed = 44 

  = 44 = carboxyl-terminal 

So here answer 

12 = C = original carboxyl terminal amino acid 

6.4 = hydrolyzed of formula 

6.4 = Cross-proton of Oxygen + 1.6 Cross-tron = 8 proton of oxygen, for a-amino alcohol,  

44 = carboxyl-terminal end

The hydrolyzed will contain one molecule of an a-amino alcohol corresponding to the original carboxyl-terminal amino acids, this can be easily identified by Sikander Aqeel method, all the other residues will be found as free amino acids, another method involves use of the enzyme carboxpeptidase,    

Now you should never forget that two chromosomes are jointed with each another into the cell for make pair of metabolism, if two chromosomes are feel presences of Carboxyl-terminal then the Carbon function will be activate into the one pair of chromosomes,          

Carboxyl-terminal = COO = 44 * 12 activate carbon atom = 528 

                                      = 528 + 64 [4(OH ion)] = 592 

                                      = 592 mole Original peptide 

I know very well, that 16692180 functions are working in one cell, today we need a special theory of cell to understand, supposed one chromosome contain of 206 threads, then 46.25 chromosome will be contain on 9527.5 threads, 

16692180 / 9527.5 = 1752 light second distance of earth from sun, 

And the special distance is very important to special micro-organisms, if we increases distance of earth from sun, then these micro-organisms will be gone in other system, where energy value increased, supposed 

One cell functions = 16692180 / 20 amino acids = 834609 

                           = 834609 / 9527.5 thread of cell = 87.6 

                           = 87.6 = 88 = 44 + 44, = COO- + CO2 energy

Here every thread is involve in energy produce system for continue the life of cell,