(Bio Mathematical Lab of Sikander Aqeel)
CHAPTER 3 PROTEINS
Proteins
(2/29/2016)
Amino Acid Sequence of Polypeptide Chain:
Perhaps you have been read several method to identify the carboxyl-terminal residue, in one the terminal carboxyl of the polypeptide is reduce to a hydroxyl group, If the polypeptide chain is that completely hydrolyzed, the hydrolyzed will contain one molecule of an a-amino alcohol corresponding to the original carboxyl-terminal amino acids,
Peptide = C7H8N2O4 = 84 + 10 + 28 + 64 = 186 mole
a-amino acid = CH3CH(NH2)COOH = C3H7N1O2 = 36 + 8.75 + 14 + 32 = 90.75 mole
For example
= a2 / b2 = c2
= a2 = Peptide and b2 = a-amino acid = c2
= a2 = 186 and b2 = 90.75 = c2
= a186 / b90.75 = c2
= 34596 / 8235.5625 = c2
= a / b = 4.20 = c2
= a / b = 4.20
= a / b = 4.20 * 12 (C) = 50.4
= a / b = 50.4 – 6.4 hydrolyzed = 44
= 44 = carboxyl-terminal
So here answer
12 = C = original carboxyl terminal amino acid
6.4 = hydrolyzed of formula
6.4 = Cross-proton of Oxygen + 1.6 Cross-tron = 8 proton of oxygen, for a-amino alcohol,
44 = carboxyl-terminal end
The hydrolyzed will contain one molecule of an a-amino alcohol corresponding to the original carboxyl-terminal amino acids, this can be easily identified by Sikander Aqeel method, all the other residues will be found as free amino acids,
(3/1/2016)
Another method involves use of the enzyme carboxpeptidase, which specifically hydrolyzes the carboxyl-terminal peptide bond of polypeptides, measurement of these relative rates of releases of amino acids by the action of this enzyme permits identification of the carboxyl-terminal residue
Peptide = C7H8N2O4 = 84 + 10 + 28 + 64 = 186 mole
Enzyme = Oxygen + Hydrogen = 19.5
Enzyme = O1 + H3.5 = 19.5 enzyme number
a-amino acid = CH3CH(NH2)COOH = C3H7N1O2 = 36 + 8.75 + 14 + 32 = 90.75 mole
For example
= a2 / b2 = c2
= a2 = Peptide and b2 = a-amino acid = c2
= a2 = 186 and b2 = 19.5 = c2
= a186 / b19.5 = c2
= 34596 / 381.22 = c2 7490.9025
= a / b = 90.75 = c2
= c1 = 45.375
= c2 = 90.75 = release of amino acids by the action of the enzyme
= c1 = 45.375 – 1.375 hydrolyzed = 44
= 44 = carboxyl-terminal
So here answer
19.5 enzyme action release to amino acids, which of react reduces to amino acid to convert in caboxyl-terminal, such as 45.375 release amino acid and 44 amount of carboxyl-terminal
Now you should never forget that two chromosomes are jointed with each another into the cell for make pair of metabolism, if two chromosomes are feel presences of Carboxyl-terminal then the Carbon function will be activate into the one pair of chromosomes,
Carboxyl-terminal = COO = 44 * 12 activate carbon atom = 528
= 528 + 64 [4(OH ion)] = 592
= 592 mole Original peptide
I know very well, that 16692180 functions are working in one cell, today we need a special theory of cell to understand, supposed one chromosome contain of 206 threads, then 46.25 chromosome will be contain on 9527.5 threads,
Total functions = 16692180 / 9527.5 = 1752 light second distance of earth from sun,
And the special distance is very important to special micro-organisms, if we increase distance of earth from sun, then these micro-organisms will be gone in other system, where energy value increased, supposed
One cell functions = 16692180 / 20 amino acids = 834609
= 834609 / 9527.5 thread of all chromosomes = 87.6
= 87.6 = 88 = 44 + 44, = COO- + CO2 energy
Here every thread is involve in energy produce system for continue the life of cell,
One cell functions = 16692180 / 20 amino acids = 834609
= 834609 / 5 bases = 166921.8
= 166921.8 / 9527.5 thread of all chromosomes = 17.52
= 17.52 - 0.27 = 17.25
= 17.25 = R – OH- alcohol
Here every thread is involve in alcohol produce system for continue the life of cell,
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