BIO ALGEBRA OF LIVING ORGANISMS

(Bio Mathematical Lab of Sikander Aqeel) 

CHAPTER 3 PROTEINS  

Proteins  

(3/2/2016) 

Amino Acid Sequence of Polypeptide Chain: 

The next step in determination of the amino acid sequence is to fragment the intact polypeptide into smaller pieces; the method of choice is enzymatic hydrolysis using the proteolytic enzyme Trypsin, this enzyme catalyze the hydrolysis of only those peptide bonds in which the carboxyl group is donated by either a Lysine or Arginine residue, 

Sue of overlapping from two different fragmentation procedures to establish the sequence of amino acids in a polypeptide chain of 21 residues,  

Lysine = 149.5 m/g

Arginine = 177.5 m/g 

Trypsin = 4(HCl) + CH2OH + H2O = 145 + 31.75 + 18.5 = 195.25    

Peptide = C7H8N2O4 = 84 + 10 + 28 + 64 = 186 mole / 11.625 Carbon = 16 Peptide bonds  

For example 

  = a2 / b2 = c2 

  = a2 = Trypsin and b2 = Peptide bonds = c2 

  = a2 = 195.25 and b2 = 16 = c2 

  = a195.25 / b16 = c2 

  = 38122.5625 / 256 = c2 

  = a / b = 148.91= c2  

  = a / b = 148.91 + 0.59 = 149.5 

  = a / b = 149.5 = Lysine

  = a / b = 149.5 / 3.303 (H3) donated = 45.25

  = 45.25 = COOH = carboxyl-group, the carboxyl group is donated by either a Lysine or Arginine residue   

So here answer 

3.303 (H3) donated by either a Lysine or Arginine residue

16 bonds of peptide = in which the carboxyl group is donated

Regardless of the length or amino acids sequence of the chain, 

for example (Trypsin 195.25 / 90.75 a-amino acid = 2.15 * 10 cm = 21.5 residue), 

the number of fragments products by trypsin cleavage can thus be predicted from the total number of Lysine or Arginine residues in the each chain, moreover all the fragments resulting from trypsin cleavage will have Lysine or Arginine residue at carboxyl-terminal position, the various fragments are the separated from each another by means of algebra, Each is then hydrolyzed and its amino acid content determined on another sample of each fragment               

Now you should never forget that two chromosomes are jointed with each another into the cell for make pair of metabolism, if two chromosomes are feel presences of Carboxyl-terminal then the Carbon function will be activate into the one pair of chromosomes,          

Carboxyl-group = COOH = 45.25 * 12 activate carbon atom = 543 

                                      = 543 + 49 [3(OH ion)] = 592 

                                      = 592 mole Original peptide 

I know very well, that 16692180 functions are working in one cell, today we need a special theory of cell to understand, supposed one chromosome contain of 206 threads, then 46.25 chromosome will be contain on 9527.5 threads, 

Total functions = 16692180 / 9527.5 = 1752 light second distance of earth from sun, 

And the special distance is very important to special micro-organisms, if we increase distance of earth from sun, then these micro-organisms will be gone in other system, where energy value increased, supposed 

One cell functions = 16692180 / 20 amino acids = 834609 

                           = 834609 / 9527.5 thread of all chromosomes = 87.6 

                           = 87.6 = 88 = 44 + 44, = COO- + CO2 energy

Here every thread is involve in energy produce system for continue the life of cell,  

One cell functions = 16692180 / 20 amino acids = 834609 

                           = 834609 / 5 bases = 166921.8 

                           = 166921.8 / 9527.5 thread of all chromosomes = 17.52 

                           = 17.52 - 0.27 = 17.25 

                           = 17.25 = R – OH- alcohol 

Here every thread is involve in alcohol produce system for continue the life of cell,