(Bio Mathematical Lab of Sikander Aqeel)
CHAPTER 3 PROTEINS
Proteins
(3/2/2016)
Amino Acid Sequence of Polypeptide Chain:
The next step in determination of the amino acid sequence is to fragment the intact polypeptide into smaller pieces; the method of choice is enzymatic hydrolysis using the proteolytic enzyme Trypsin, this enzyme catalyze the hydrolysis of only those peptide bonds in which the carboxyl group is donated by either a Lysine or Arginine residue,
Sue of overlapping from two different fragmentation procedures to establish the sequence of amino acids in a polypeptide chain of 21 residues,
Lysine = 149.5 m/g
Arginine = 177.5 m/g
Trypsin = 4(HCl) + CH2OH + H2O = 145 + 31.75 + 18.5 = 195.25
Peptide = C7H8N2O4 = 84 + 10 + 28 + 64 = 186 mole / 11.625 Carbon = 16 Peptide bonds
For example
= a2 / b2 = c2
= a2 = Trypsin and b2 = Peptide bonds = c2
= a2 = 195.25 and b2 = 16 = c2
= a195.25 / b16 = c2
= 38122.5625 / 256 = c2
= a / b = 148.91= c2
= a / b = 148.91 + 0.59 = 149.5
= a / b = 149.5 = Lysine
= a / b = 149.5 / 3.303 (H3) donated = 45.25
= 45.25 = COOH = carboxyl-group, the carboxyl group is donated by either a Lysine or Arginine residue
So here answer
3.303 (H3) donated by either a Lysine or Arginine residue
16 bonds of peptide = in which the carboxyl group is donated
Regardless of the length or amino acids sequence of the chain,
for example (Trypsin 195.25 / 90.75 a-amino acid = 2.15 * 10 cm = 21.5 residue),
the number of fragments products by trypsin cleavage can thus be predicted from the total number of Lysine or Arginine residues in the each chain, moreover all the fragments resulting from trypsin cleavage will have Lysine or Arginine residue at carboxyl-terminal position, the various fragments are the separated from each another by means of algebra, Each is then hydrolyzed and its amino acid content determined on another sample of each fragment
Now you should never forget that two chromosomes are jointed with each another into the cell for make pair of metabolism, if two chromosomes are feel presences of Carboxyl-terminal then the Carbon function will be activate into the one pair of chromosomes,
Carboxyl-group = COOH = 45.25 * 12 activate carbon atom = 543
= 543 + 49 [3(OH ion)] = 592
= 592 mole Original peptide
(3/3/2016)
The amino terminal acid is then identified by reaction with 2,4 dinitrofluorobenzene or reagent by algebra, with the information the amino acid sequence of all the dipeptide and tripeptide fragments resulting from Trypsin cleavage will be known, the larger peptide from the Trypsin can then be sequenced by repeated algebra stop, in the manner of amino acid sequence of each of the fragments obtained by Trypsin cleavage of the chain can be establish,
Trypsin = 4(HCl) + CH2OH + H2O = 145 + 31.75 + 18.5 = 195.25
Peptide = C7H8N2O4 = 84 + 10 + 28 + 64 = 186 mole / 21 H2O and H2 = 8.9 Peptide bonds
2,4 dinitrofluorobenzene = C6H12N2O4F = 72+15+28+64+19 = 198 mole
For example
= a2 / b2 = c2
= a2 = 2,4 dinitrofluorobenzene and b2 = Trypsin = c2
= a2 = 198 and b2 = 195.25 = c2
= a198 + b195.25 = c2
= 39204 + 38122.5625 = c2
= a + b = 77326.5625 = c2
= a + b = 77326.5625 / 278.15 = 278.15
= c2 = 278.15
= c2 = 278.15 + 90.75 a-amino acids = 368.9
= 368.9 – 8.9 peptide bonds = 360
= 360 = 2(Peptide) = establish chain of peptide
= 360 = 2(Peptide) = the larger peptide from the Trypsin can then be sequenced by repeated of Sikander Aqeel stop, in the manner of amino acid sequence of each of the fragments obtained by Trypsin cleavage of the chain can be establish,
So here answer
Trypsin cleavage can establish to peptide
Manner of amino acid by benzene nitrogen and fluorine, or 2,4 dinitrofluorobenzene
Supposed a cell function = 16692180 numbers / 360 two peptide = 46367.16
= 46367 / 90.75 a-amino acid = 510.93
= 511 + 81 (C6.75) of proteins = 592
= 592 mole Original peptide
Supposed a cell function = 16692180 numbers / 360 two peptide = 46367.16
= 46367 / 1752 light sec = 26.46
= 27 = age in which two peptide establish,
= 27 = year age
Supposed a cell function = 16692180 numbers / 180 one peptide = 92734.33
= 92734 / 1752 light sec = 52.93
= 53 = age in which one peptide establish
= 25.07 = year age
So the distance of earth from sun is a clock of cells, when age increases then clock of cells becomes weak to do fast function of cells, and health start to fall down by reason of slow walk of clock, I am full trying to convert your biology into the time, because the time is most big medicine, If you have not time then you have not medicine of life,
Logic of Clock of Cells
1 to 27 to 53 age = three peptide and minimum two peptide
53 to 73 age = only one peptide
73 to 93 age = only one and too weak peptide, which cannot restart function of cells,
I know very well, that 16692180 functions are working in one cell, today we need a special theory of cell to understand, supposed one chromosome contain of 206 threads, then 46.25 chromosome will be contain on 9527.5 threads,
Total functions = 16692180 / 9527.5 = 1752 light second distance of earth from sun,
And the special distance is very important to special micro-organisms, if we increase distance of earth from sun, then these micro-organisms will be gone in other system, where energy value increased, supposed
One cell functions = 16692180 / 20 amino acids = 834609
= 834609 / 9527.5 thread of all chromosomes = 87.6
= 87.6 = 88 = 44 + 44, = COO- + CO2 energy
Here every thread is involve in energy produce system for continue the life of cell,
One cell functions = 16692180 / 20 amino acids = 834609
= 834609 / 5 bases = 166921.8
= 166921.8 / 9527.5 thread of all chromosomes = 17.52
= 17.52 - 0.27 = 17.25
= 17.25 = R – OH- alcohol
Here every thread is involve in alcohol produce system for continue the life of cell,
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