(Bio Mathematical Lab of Sikander Aqeel)
CHAPTER 3 PROTEINS
Proteins
(3/12/2016)
Amino Acid Sequence of Polypeptide Chain:
The common approach described above was first devised by F, Sanger in his pioneering work on the amino acid sequence of the insulin, which he completed in 1953 and foe which he was awarded of the Nobel Prize, Complete amino acid sequence of “Bovine insulin” which consist on two polypeptide chains,
The A chain which has 21 amino acids residues
And B chain which has 30 amino acids
The two chains which are cross-linked by disulfide bridges of cystine residue,
Upper end of amino acid
Gly Phe
| |
Ile Val
| |
Val Asn
| |
Glu Gln
| |
5- Glu His -5 ----first 10 amino acids sequence by Sulfur oxide
| |
|-------Cys Leu
| | |
| Cys ------S—S------- Cys
| | |
S Ala Gly
| | |
S Ser Ser
| | |
| 5-Val His-5--- second 10 amino acids sequence by four Sulfur
| | |
|-------Cys Leu
| |
Ser Val
| |
Leu Glu
| |
Tyr Ala
| |
5-Gln Leu-5--- third 10 amino acids sequence by Respiratory proteins
| |
Leu Tyr
| |
Glu Leu
| |
Asn Val
| |
Tyr |-----Cys
| | |
5-Cys ------S—S--| Gly-5--- fourth 10 amino acids sequence by hormone
| |
Asn Glu
A-chain |
Arg
|
Gly
|
Phe
|
Phe
|
Try
|
Thr
|
Pro
|
Lys
|
Ala
|
B-chain
Second end on Carboxyl-terminal
The first and last always occur same, if algebra be in balance, here we have fourth 10 amino acids of A-chain and B-chain
Leu Tyr
| |
Glu Leu
| |
Asn Val
| |
Tyr |-----Cys
| | |
5-Cys ------S—S--| Gly-5--- fourth 10 amino acids sequence by Hormone
Leucine = C6H13NO2 = 134.25 m/g
Glutamate = C5H9NO4 = 149.25 m/g
Asparagine = C4H8N2O3 = 134 m/g
Tyrosine = C9H11NO3 = 183.75 m/g
Cysteine = C3H7NO2S = 122.75 m/g
Total = 724 = A-chain
Tyrosine = C9H11NO3 = 183.75 m/g
Leucine = C6H13NO2 = 134.25 m/g
Valine = C5H11NO2 = 119.75 m/g
Cysteine = C3H7NO2S = 122.75 m/g
Glycine = C2H5NO2 = 76.25 m/g
Total = 636.75 = B-chain
For example
= a2 + b2 = c2
= a2 = A-chain and b2 = B-chain = c2
= a2 = 724 and b2 = 636.75 = c2
= a724 + b636.75 = c2
= 524176 + 405450.5625 = c2
= a + b = 929626.5625 = c2
= a + b = 929626.5625 / 964 = 964
= a + b = 964 = Polypeptide
= a + b = 964 / 64 (S2) = 15.0625 = cross-linked of Hormone
= a + b = 15.0625 * 12.348547 (pH2) = 185.999
= a + b = 186 = peptide
= a + b = 964 * 6 radius = 5784 = cross-linked of
= a + b = 5784 – 51 (3OH) = 5733
= a + b = 5733 = molecular weight of insulin (bovine)
= a + b = 964 = Polypeptide
= a + b = 964 / 21 (amino acids of A-chain) = 45.90
= a + b = 45.90 - 0.65 = 45.25
= a + b = 45.25 = COOH = carboxyl-group,
= a + b = 964 = Polypeptide
= a + b = 964 / 21.9090 (H2O + H3) = 44.00
= a + b = 44.00 = carboxyl-terminal end by B-chain, from reason of same first and last,
= a + b = 964 = Polypeptide
= a + b = 964 / 128 (S4) = 7.53125
= a + b = 7.53125 - 0.53125 = 7
= a + b = 7 Iso-electric pH of Myoglobin from Hormone
Here first cleaved by acidic oxide before their sequence we determined,
Soon other investigators reported the sequence of amino acids in the human adrenocorticotrophine, the hormone of the anterior pituitary gland
Carboxyl-group = COOH = 45.25 * 12 activate carbon atom = 543
= 543 + 49 [3(OH ion)] = 592
= 592 mole Original peptide
Supposed a cell function = 16692180 numbers / 964 Polypeptide = 17315.53
= 17316 / 44 Carboxyl-terminal = 393.54
= 394 - 29 (N2H) = 365
= 365 day biological system of earth,
Supposed a cell function = 16692180 numbers / 964 Polypeptide = 17315.53
= 17316 / 1752 light sec = 9.88
= 10 = age
= 10 = year age of Bovine insulin by Hormone,
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