BIO ALGEBRA OF LIVING ORGANISMS

(Bio Mathematical Lab of Sikander Aqeel) 

CHAPTER [3] PROTEINS  

Proteins  

(3/17/2016) 

Amino Acid Sequence of Polypeptide Chain:  

The next important landmark was the identification of the amino acid sequence of the two types polypeptide in crystalline hemoglobin, 

This was the first sequence **ysis of oligomeric or multichain proteins, 

The hemoglobin contain on 4 polypeptide chain  

Polypeptide = identical a chain = 141 residues 

Polypeptide = identical b chain = 146 residues    

        The Human Adrenocorticotrophin and S – S linkage 

1 polypeptide = Ser, Tyr, Ser, Met, Glu, His, Phe, Arg, Trp, Gly = 10 amino acids 

2 polypeptide = Lys, Pro, Val, Gly, Lys, Lys, Arg, Arg, Pro, Val = 10 amino acids                

          Lys                         Lys 

            |                            | 

          Pro                         Arg 

            |                            | 

          Val                         Arg 

            |                            | 

          Gly                         Val 

            |                            | 

      5- Lys                         Gly -5 ----second 10 amino acids sequence by Sulfur oxide  

Identical a chain          Identical b chain  

          Lysine = C6H14N2O2 = 149.5 m/g

            Proline = C5H9NO2 = 117.25 m/g

            Valine = C5H11NO2 = 119.75 m/g

                  Glycine = C2H5NO2 = 76.25 m/g

          Lysine = C6H14N2O2 = 149.5 m/g

                               Total = 612.25 = Identical a chain 

            Lysine = C6H14N2O2 = 149.5 m/g

         Arginine = C6H14N4O2 = 177.5 m/g

         Arginine = C6H14N4O2 = 177.5 m/g

             Valine = C5H11NO2 = 119.75 m/g

             Glycine = C2H5NO2 = 76.25 m/g

                                Total = 700.5 = Identical b chain   

For example 

  = a2 + b2 = c2 

  = a2 = Identical a chain and b2 = Identical b chain = c2 

  = a2 = 612.25 and b2 = 700.5 = c2 

  = a612.25 + b700.5 = c2 

  = 374850.0625 + 490700.25 = c2 

  = a + b = 865550.3125 = c2  

  = a + b = 865550.3125 / 930.3 = 930.3

  = a + b = 930.3 = Polypeptide

  = a + b = 930.3 / 64 (S2) = 14.5359375 = cross-linked of Sulfur oxide

  = a + b = 14.5359375 * 6.8 (Hemoglobin Iso pH) = 98.844375 

  = a + b = 98.84 + 13.16 CH = 112 

  = a + b = 112 = Residues 

  = a + b = 930.3 / 64 (S2) = 14.5359375 = cross-linked of Sulfur oxide

  = a + b = 14.5359375 * 7 (Myoglobin Iso pH) = 101.7515625 

  = a + b = 101.75 + 13.25 CH = 115 

  = a + b = 115 = Residues 

  = a + b = 930.3 * 69.33 (2CH2OH + H4) = 64497.699

  = a + b = 64497.699 + 2.301 H2 = 64500 

  = a + b = 64500 = molecular weight of (Hemoglobin)     

  = a + b = 930.3 = Polypeptide

  = a + b = 930.3 / 20.55 (H2O + H2) = 45.27

  = a + b = 45.25 = COOH = carboxyl-group, 

  = a + b = 930.3 = Polypeptide

  = a + b = 930.3 / 21.14 (H2O + H2) = 44.00

  = a + b = 44.00 = carboxyl-terminal end

  = a + b = 930.3 = Polypeptide

  = a + b = 930.3 / 128 (S4) = 7.26796875

  = a + b = 7.26796875 - 0.46796875 (H) = 6.8 

  = a + b = 6.8 Iso-electric pH of hemoglobin by 4 sulfur linkage    

Carboxyl-group = COOH = 45.25 * 12 activate carbon atom = 543 

                                      = 543 + 49 [3(OH ion)] = 592 

                                      = 592 mole Original peptide 

Supposed a cell function = 16692180 numbers / 930.3 Polypeptide = 17942.79

                                    = 17943 / 44 Carboxyl-terminal = 407.79

                                    = 408 day biological system of earth and hemoglobin, 

Supposed a cell function = 16692180 numbers / 930.3 Polypeptide = 17942.79

                                    = 17943 / 1752 light sec = 10.24

                                    = 10 = age

                                    = 10 = year age of protein of hemoglobin, 

This feat was carried out by groups of different algebra of Sikander Aqeel,