BIO ALGEBRA OF LIVING ORGANISMS

(Bio Mathematical Lab of Sikander Aqeel) 

CHAPTER [3] PROTEINS  

Proteins  

(3/20/2016) 

Amino Acid Sequence of Polypeptide Chain:  

The next important landmark was the identification of the amino acid sequence of the two types polypeptide in crystalline hemoglobin, 

This was the first sequence **ysis of oligomeric or multichain proteins, 

The hemoglobin contain on 4 polypeptide chain  

Polypeptide = identical a chain = 141 residues 

Polypeptide = identical b chain = 146 residues    

        The Human Adrenocorticotrophin and S – S linkage 

1 polypeptide = Ser, Tyr, Ser, Met, Glu, His, Phe, Arg, Trp, Gly = 10 amino acids 

2 polypeptide = Lys, Pro, Val, Gly, Lys, Lys, Arg, Arg, Pro, Val = 10 amino acids 

3 polypeptide = Lys, Val, Tyr, Pro, Asp, Ala, Gly, Glu, Asp, Gln = 10 amino acids 

4 polypeptide = Ser, Ala, Glu, Ala, Phe, Pro, Leu, Glu, Phe, = 9 amino acids                                               

          Ser                         

            |                            

          Ala                         Pro 

            |                            | 

          Glu                         Leu 

            |                            | 

          Ala                         Glu 

            |                            | 

      5- Phe                        Phe -4 ----second 9 amino acids sequence by Sulfur oxide  

Identical a chain          Identical b chain 

                Serine = C3H7NO3 = 106.75 m/g 

               Alanine = C3H7NO2 = 90.75 m/g 

           Glutamate = C5H9NO4 = 149.25 m/g 

               Alanine = C3H7NO2 = 90.75 m/g 

    Phenylalanine = C9H11NO2 = 167.75 m/g

                                   Total = 605.25 = Identical a chain  

                 Proline = C5H9NO2 = 117.25 m/g 

              Leucine = C6H13NO2 = 134.25 m/g 

            Glutamate = C5H9NO4 = 149.25 m/g 

     Phenylalanine = C9H11NO2 = 167.75 m/g

                                   Total = 568.5 = Identical b chain   

For example 

  = a2 + b2 = c2 

  = a2 = Identical a chain and b2 = Identical b chain = c2 

  = a2 = 605.25 and b2 = 568.5 = c2 

  = a605.25 + b568.5 = c2 

  = 366327.5625 + 323192.25 = c2 

  = a + b = 689519.8125 = c2  

  = a + b = 689519.8125 / 830.4 = 830.4

  = a + b = 830.4 = Polypeptide

  = a + b = 830.4 / 64 (S2) = 12.975 = cross-linked of Sulfur oxide

  = a + b = 12.975 * 6.8 (Hemoglobin Iso pH) = 88.23

  = a + b = 88.23 + 23.77 (C2) = 112 

  = a + b = 112 = Residues 

  = a + b = 830.4 / 64 (S2) = 12.975 = cross-linked of Sulfur oxide

  = a + b = 12.975 * 7 (Myoglobin Iso pH) = 90.825

  = a + b = 90.825 + 24.175 (C2) = 115 

  = a + b = 115 = Residues 

  = a + b = 830.4 * 77.67 (CH2OH + H12) = 64497.168

  = a + b = 64497.168 + 2.832 H2 = 64500 

  = a + b = 64500 = molecular weight of (Hemoglobin)     

  = a + b = 830.4 = Polypeptide

  = a + b = 830.4 / 18.35 (H2O) = 45.25

  = a + b = 45.25 = COOH = carboxyl-group, 

  = a + b = 830.4 = Polypeptide

  = a + b = 830.4 / 18.87 (H2O) = 44.00

  = a + b = 44.00 = carboxyl-terminal end

  = a + b = 830.4 = Polypeptide

  = a + b = 830.4 / 128 (S4) = 6.4875

  = a + b = 6.4875 + 0.3125 = 6.8 

  = a + b = 6.8 Iso-electric pH of hemoglobin by 4 sulfur linkage    

Carboxyl-group = COOH = 45.25 * 12 activate carbon atom = 543 

                                      = 543 + 49 [3(OH ion)] = 592 

                                      = 592 mole Original peptide 

Supposed a cell function = 16692180 numbers / 830.4 Polypeptide = 20101.37

                                    = 20101 / 44 Carboxyl-terminal = 456.84

                                    = 457 day biological system of earth and hemoglobin, 

Supposed a cell function = 16692180 numbers / 830.4 Polypeptide = 20101.37

                                    = 20101 / 1752 light sec = 11.47

                                    = 12 = age

                                    = 12 = year age of protein of hemoglobin, 

This feat was carried out by groups of different algebra of Sikander Aqeel, 

Table: for little age and ** age

Little age = 112 amino acids + 29 N2 = 141 amino acids for ** 

Little age = 115 amino acids + 31 O2 = 146 amino acids for **,      

Forms of Human Hemoglobin, 

A hemoglobin molecules consists of four polypeptide chain of two different primary structure, In common form of human Little age hemoglobin Hb A1, two chains of kind are designated the a-chain and second two chain of same kind are designated the b-chain the polypeptide chain composition of Hb A1, is therefore a2 b2 the a-polypeptide chain consist of 112 amino acids, and b-polypeptide chain contain on 115 amino acids by sulfur oxide, 

While Hb A1, is the important form of hemoglobin in the Little age human, other forms of hemoglobin predominate in the blood of the human fetus, these early form of human hemoglobin contain two of the tetramer molecule differs in amino acids sequence from that of the b-chain of Little age Hb A1, the a-amino form of Little age hemoglobin Hb A2, comprise about 2% of normal Little age hemoglobin and it composed of two a–chain,