(Three peptide in mathematical machine of Sikander Aqeel)
THREE PEPTIDES AND EARTH
CELL MEMBRANE OF HUMAN
Cell membrane = 100 % = 40 % lipids + 55 % protein + 5 % carbohydrate
Earth = 365 days
= a2 + b2 = c2
= a2 Earth + b2 Cell membrane = c2
= a2 365 + b2 100 = c2
= a2 133225 + b2 10000 = c2
= a + b = 143225 = c2
= a + b = 143225 / 378.45 = 378.45
= a + b = 378.45 / 2.5 (H2= A//T DNA) = 151.38
= a + b = 151.38 - 5.37 (H4) = 156.75
= a + b = 156.75 = Di-peptide
The earth atmosphere which belongs with 365 day of peptide,
Peptide = 85.00, = C4H4O2
Di-Peptide = 156.75, = C6H7N2O3
Tri-Peptide = 224.00, = C9H8N3O4
Total three peptide = 465.75
= 465.75 – 100 Cell membrane = 365.75
= 365.75 – 0.75 % use of membrane = 365
= 365 biological days of a cell,
Use of Cell membrane per minute = 0.75 %
Use of water in cells = 18.5 / 0.75 % = 24.666666666666666666666666666667
= 24.666666666666666666666666666667 * 24 hour = 592
= 592 unit use of water in a cell from the Cell membrane,
= 592 / 32 (O2 of atmosphere) = 18.5,
Use of water per cell = 592 unit / 100 Cell membrane = 5.92
= 5.92 liter water need of body per day,
(7/1/2016)
The Cell membrane absorption is 0.75 % nutrients per minute, for three peptides, and it will be called the use of cell membrane, now we have (ALP) tissues protein result to know total (ALP) tissues protein in complete body
ALP - blood test
Alkaline phosphates (ALP) are a protein found in all body tissues. Tissues with higher amounts of ALP include the liver, bile ducts, and bone.
A blood test can be done to measure the level of ALP.
A related test is the ALP is enzyme test.
Normal Results (ALP) tissues protein
The normal range is 44 to 147 IU/L (international units per liter)
The normal range = 147 IU/L for maximum weight and young age
The normal range = 44 IU/L for minimum weight and over age
LOWER HEALTHY
(ALP) tissues protein = 44 / 0.75 % = 58.666666666666666666666666666667
= 58.666666666666666666666666666667 * 24 hour = 1408
= 1408 alkaline phosphates (ALP) tissues protein from the Cell membrane,
= 1408 / 32 (O2 of atmosphere) = 44,
Use of tissues protein = 1408 unit / 100 Cell membrane = 14.08
= 14.08 liter (ALP) tissues protein in body like lower healthy,
So the 14.08 liter tissues protein in whole body, which will be counted thin body and lower healthy,
HIGH HEALTHY
(ALP) tissues protein = 147 / 0.75 % = 196
= 196 * 24 hour = 4704
= 4704 alkaline phosphates (ALP) tissues protein from the Cell membrane,
= 4704 / 32 (O2 of atmosphere) = 147,
Use of tissues protein = 4704 unit / 100 Cell membrane = 47.04
= 47.04 liter (ALP) tissues protein in body like high healthy,
So the 47.04 liter tissues protein in whole body, which will be counted high healthy,