Sikander Aqeel

ALP - BLOOD TEST

Jul 1st 2016, 12:10 pm

Posted by aqeelsika

351 Views

(Three peptide in mathematical machine of Sikander Aqeel)

THREE PEPTIDES AND EARTH

CELL MEMBRANE OF HUMAN

Cell membrane = 100 % = 40 % lipids + 55 % protein + 5 % carbohydrate

Earth = 365 days

= a2 + b2 = c2

= a2 Earth + b2 Cell membrane = c2

= a2 365 + b2 100 = c2

= a2 133225 + b2 10000 = c2

= a + b = 143225 = c2

= a + b = 143225 / 378.45 = 378.45

= a + b = 378.45 / 2.5 (H2= A//T DNA) = 151.38

= a + b = 151.38 - 5.37 (H4) = 156.75

= a + b = 156.75 = Di-peptide

The earth atmosphere which belongs with 365 day of peptide,

Peptide = 85.00, = C4H4O2

Di-Peptide = 156.75, = C6H7N2O3

Tri-Peptide = 224.00, = C9H8N3O4

Total three peptide = 465.75

= 465.75 – 100 Cell membrane = 365.75

= 365.75 – 0.75 % use of membrane = 365

= 365 biological days of a cell,

Use of Cell membrane per minute = 0.75 %

Use of water in cells = 18.5 / 0.75 % = 24.666666666666666666666666666667

= 24.666666666666666666666666666667 * 24 hour = 592

= 592 unit use of water in a cell from the Cell membrane,

= 592 / 32 (O2 of atmosphere) = 18.5,

Use of water per cell = 592 unit / 100 Cell membrane = 5.92

= 5.92 liter water need of body per day,

(7/1/2016)

The Cell membrane absorption is 0.75 % nutrients per minute, for three peptides, and it will be called the use of cell membrane, now we have (ALP) tissues protein result to know total (ALP) tissues protein in complete body

ALP - blood test

Alkaline phosphates (ALP) are a protein found in all body tissues. Tissues with higher amounts of ALP include the liver, bile ducts, and bone.

A blood test can be done to measure the level of ALP.

A related test is the ALP is enzyme test.

Normal Results (ALP) tissues protein

The normal range is 44 to 147 IU/L (international units per liter)

The normal range = 147 IU/L for maximum weight and young age

The normal range = 44 IU/L for minimum weight and over age

LOWER HEALTHY

(ALP) tissues protein = 44 / 0.75 % = 58.666666666666666666666666666667

= 58.666666666666666666666666666667 * 24 hour = 1408

= 1408 alkaline phosphates (ALP) tissues protein from the Cell membrane,

= 1408 / 32 (O2 of atmosphere) = 44,

Use of tissues protein = 1408 unit / 100 Cell membrane = 14.08

= 14.08 liter (ALP) tissues protein in body like lower healthy,

So the 14.08 liter tissues protein in whole body, which will be counted thin body and lower healthy,

HIGH HEALTHY

(ALP) tissues protein = 147 / 0.75 % = 196

= 196 * 24 hour = 4704

= 4704 alkaline phosphates (ALP) tissues protein from the Cell membrane,

= 4704 / 32 (O2 of atmosphere) = 147,

Use of tissues protein = 4704 unit / 100 Cell membrane = 47.04

= 47.04 liter (ALP) tissues protein in body like high healthy,

So the 47.04 liter tissues protein in whole body, which will be counted high healthy,

DISEASES OF (ALP) (7/2/2016)

Lower-than-normal ALP levels

• The Hypophosphatasia is disease from lower-than-normal ALP levels, or Hypophosphatasia (HPP) is a rare genetic disorder characterized by the abnormal development of bones and teeth. These abnormalities occur due to defective mineralization, the process by which bones and teeth take up minerals such as calcium and phosphorus.

Hypophosphatasia is caused by mutations in the tissue nonspecific alkaline phosphatase (ALPL) gene. This gene is also known as the TNSALP gene. Such mutations lead to low levels of the tissue nonspecific alkaline phosphatase enzyme. Depending on the specific form, hypophosphatasia can be inherited in an autosomal recessive or autosomal dominant manner.

Cell membrane = 100 % = 40 % lipids + 55 % protein + 5 % carbohydrate

Cell membrane = 55 % protein

(ALP) tissues protein = 14.08 liter in lower condition

= a2 + b2 = c2

= a2 lower (ALP) + b2 Cell membrane = c2

= a2 14.08 + b2 55 % protein = c2

= a2 198.2464 + b2 3025 = c2

= a + b = 3223.2464 = c2

= a + b = 3223.2464 / 56.77 = 56.77

= a + b = 56.77 / 2.5 (H2= A//T DNA) = 22.708

= a + b = 22.708 - 0.458 = 22.25

= a + b = 22.25 = H2O + H3 of DNA base