(Three peptide in mathematical machine of Sikander Aqeel)
THREE PEPTIDES AND EARTH
CELL MEMBRANE OF HUMAN
Cell membrane = 100 % = 40 % lipids + 55 % protein + 5 % carbohydrate
Earth = 365 days
= a2 + b2 = c2
= a2 Earth + b2 Cell membrane = c2
= a2 365 + b2 100 = c2
= a2 133225 + b2 10000 = c2
= a + b = 143225 = c2
= a + b = 143225 / 378.45 = 378.45
= a + b = 378.45 / 2.5 (H2= A//T DNA) = 151.38
= a + b = 151.38 - 5.37 (H4) = 156.75
= a + b = 156.75 = Di-peptide
The earth atmosphere which belongs with 365 day of peptide,
Peptide = 85.00, = C4H4O2
Di-Peptide = 156.75, = C6H7N2O3
Tri-Peptide = 224.00, = C9H8N3O4
Total three peptide = 465.75
= 465.75 – 100 Cell membrane = 365.75
= 365.75 – 0.75 % use of membrane = 365
= 365 biological days of a cell,
Use of Cell membrane per minute = 0.75 %
Use of water in cells = 18.5 / 0.75 % = 24.666666666666666666666666666667
= 24.666666666666666666666666666667 * 24 hour = 592
= 592 unit use of water in a cell from the Cell membrane,
= 592 / 32 (O2 of atmosphere) = 18.5,
Use of water per cell = 592 unit / 100 Cell membrane = 5.92
= 5.92 liter water need of body per day,
The Cell membrane absorption is 0.75 % nutrients per minute, for three peptides, and it will be called the use of cell membrane, now we have (ALP) tissues protein result to know total (ALP) tissues protein in complete body
ALP - blood test
Alkaline phosphates (ALP) are a protein found in all body tissues. Tissues with higher amounts of ALP include the liver, bile ducts, and bone.
A blood test can be done to measure the level of ALP.
A related test is the ALP is enzyme test.
Normal Results (ALP) tissues protein
The normal range is 44 to 147 IU/L (international units per liter)
The normal range = 147 IU/L for maximum weight and young age
The normal range = 44 IU/L for minimum weight and over age
LOWER HEALTHY
(ALP) tissues protein = 44 / 0.75 % = 58.666666666666666666666666666667
= 58.666666666666666666666666666667 * 24 hour = 1408
= 1408 alkaline phosphates (ALP) tissues protein from the Cell membrane,
= 1408 / 32 (O2 of atmosphere) = 44,
Use of tissues protein = 1408 unit / 100 Cell membrane = 14.08
= 14.08 liter (ALP) tissues protein in body like lower healthy,
So the 14.08 liter tissues protein in whole body, which will be counted thin body and lower healthy,
HIGH HEALTHY
(ALP) tissues protein = 147 / 0.75 % = 196
= 196 * 24 hour = 4704
= 4704 alkaline phosphates (ALP) tissues protein from the Cell membrane,
= 4704 / 32 (O2 of atmosphere) = 147,
Use of tissues protein = 4704 unit / 100 Cell membrane = 47.04
= 47.04 liter (ALP) tissues protein in body like high healthy,
So the 47.04 liter tissues protein in whole body, which will be counted high healthy,
WILSON DISEASE (7/15/2016)
Lower-than-normal ALP levels
• 1 = Hypophosphatasia
• 2 = Malnutrition
• 3 = Wilson disease
•
• Wilson disease has a range of clinical manifestations, from an asymptomatic state to fulminant hepatic failure, chronic liver disease with or without cirrhosis, neurologic, and psychiatric manifestations
• Consider hepatic Wilson disease in the differential diagnosis of any unexplained chronic liver disease, especially in individuals younger than 40 years. The condition may also manifest as acute hepatitis. Hepatic dysfunction is the presenting feature in more than half of patients. The 3 major patterns of hepatic involvement are as follows: (1) chronic active hepatitis, (2) cirrhosis, and (3) fulminant hepatic failure. The most common initial presentation is cirrhosis.
•
So the Malnutrition goes in tuberculosis, gastroenteritis, pneumonia, malaria, and measles, and thsese all infections goes in definicey of proteins and vitamins for rise-up Wilson disease, like
• Patients in the parkinsonian group (45%) - Distinguished by paucity of expression and movement
• Patients in the pseudosclerotic group (24%) - Had tremor resembling multiple sclerosis
• Patients in the dystonic group (15%) - Characterized by hypertonicity associated with abnormal limb movements.
• Patients in the choreic group (11%) - Predominantly characterized by choreoathetoid abnormal movements associated with dystonia
Psychiatric features include emotional lability, impulsiveness, disinhibition, and self-injurious behavior. The reported percentage of patients with psychiatric symptoms as the presenting clinical feature is 10-20%. The range of psychiatric abnormalities associated with Wilson disease has been divided into 4 basic categories, as follows:
• Behavioral
• Affective
• Schizophrenic-like
• Cognitive
•
PATIENTS IN THE PARKINSONIAN GROUP (45%)
= Distinguished by paucity of expression and movement,
The paucity of expression and movement are contains on frontal lobe with thinking, memory, behaveriour and movement,
Basically strong memory can cove paucity of expression and movement, while strong memory belongs with over quantity of oxygen into the frontal lobe, the Vitamin-B6 make better to frontal lobe from 2.50 percent quantity, or parkinsonian group blongs with 2.50 % less Vitamin-B6,
FOR EXAMPLE BEGINNING OF ENERGY,
Adenine + ribose sugar
A = energy
= a2 + b2 = c2
= a2 (Adenine) + b2 ribose sugar = c2
= a2 (C5H5N5) + b2 (C5H10O4) = c2
= a2 (135.13 g/mol) + b2 (136.5 g/mol) = c2
= a2 (18260.1169) + b2 (18632.25) = c2
= a + b = 36892.3669 = c2
= a + b = 36892.3669 / 45.25 (COOH) = 815.300
= a + b = 815
B = Phosphate
= a2 / b2 = c2
= a2 (815) / b2 (PO4) = c2
= a2 (815) / b2 (95) = c2
= a2 (664225) / b2 (9025) = c2
= a / b = 73.59 = c2
= a / b = 74 / 8.60 = 8.60
= a / b = 8.60 / 2.5 (H2= A//T DNA) = 3.44
= a / b = 3.44 + 0.31 = 3.75
= a / b = 3.75 = (H3= C///G DNA)
= a / b = (H2= A//T DNA) + (H3= C///G DNA) = two Polynucleotide chains,
= a / b = (H2= A//T DNA) + (H3= C///G DNA) = end of energy,
C = 2.50 % Vitamin-B6 = 1355 (2.50 * 542 = 1355)
= a2 / b2 = c2
= a2 (Vitamin-B6) / b2 (two Polynucleotide) = c2
= a2 (1355) / b2 (2.5 + 3.75) = c2
= a2 (1355) / b2 (6.25) = c2
= a2 (1836025) / b2 (39.0625) = c2
= a / b = 47002.24 = c2
= a / b = 47002.24 / 216.85 = 216.75
= a / b = 216.75 / 2.5 (H2= A//T DNA) = 86.7
= a / b = 86.7 * 6.25 two Polynucleotide = 541.875
= a / b = 542 = Vitamin-B6 = Pyridoxine + Pyridoxamine + Pyridoxal + H24
= a / b = 542 = H24 30 + C8H11NO3 171.75 + C8H12N2O2 171 + C8H9NO3 169.25 = 542
CONDITION OF DNA FROM PARKINSONIAN GROUP
= a / b = 216.75 / 2.5 (H2= A//T Polynucleotide) = 86.7
= a / b = 86.7 / 3.75 (H3= C///G Polynucleotide) = 23.12
= a / b = 23.12 * 50 ratio = 1156
= a / b = 1156 / 34A = 34A
= a / b = 34A = distance of one helix
= Parkinsonian group = 34A / 10 mononucleotide = 3.4
= = 3.4A distance between two base pair,
So 2.50 % over vitamin-B6 is equal to 3.4A healthy distance between two base pair,
For easiness and remembrances
0 = normal lower range = 44 = ALP – blood test
• 1 = Hypophosphatasia lower range = 43, 40, 39, ALP – blood test
• 2 = Protein deficiency lower rang = 38, 37, ALP – blood test
• 3 = Malnutrition lower range = 36, 35, ALP – blood test
• 4 = Wilson disease lower range =
And we can change rate at the end for Wilson disease,
OTHER CONDITIONS FOR WHICH THE TEST MAY BE MORE DONE:
• Alcoholic liver disease (hepatitis/cirrhosis)
• Alcoholism
• Biliary stricture
• Gallstones
• Giant cell (temporal, cranial) arteritis
• Multiple endocrine neoplasia (MEN) II
• Pancreatitis
• Renal cell carcinoma