(Bio Mathematical Lab of Sikander Aqeel)
CHAPTER [3] PROTEINS
Proteins
(8/19/2016)
Charge and Chemical Properties of Amino acids and Proteins,
An understanding of protein requires knowledge of the ionizable side chain groups of the common amino acids, these ionizable groups common to proteins and amino acids, the acid form of the respective ionizable groups are on the left of the sum, while the respective properties base are on the right side, characteristic of the acid form is that nitrogen-containing groups are positively charged, whereas the acid forms that contain oxygen and sulfur atoms are natural,
Where acid group found Acid form = Base form,
C6H14N4O2-Arginine R-NH-C=NH2 = R-NH-C=NH + H = 11.5-12.5 pK
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NH2 NH2
Guanidinium = Guanidio
Left side = C6H14N4O2 = 177.5
Guanidio = R-NH-C=NH + H
|
NH2= 60.25
= a2 - b2 = c2
= a2 (Left side) + b2 (Guanidio) = c2
= a2 (177.5) + b2 (60.25) = c2
= a + b = (31506.25) + b (3630.0625) = c2
= a + b = 35136.3125 = c2
= a + b = 35136.3125 / 187.44 = 187.45
= a + b = 187.45 / 1.5 Optimum pH of stomach pepsin = 124.96
= a + b = 125 / 2.118 Optimum pH of stomach peptide bond = 59
= a + b = 59 = NH-C=NH
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NH2 = 59 = Guanidio at right side
= a + b = 44 = NH-C=NH + H+
|
NH2 = 60.25 = Guanidio at right side
= a + b = 60.25 / 5 hydrogen atoms = 12.05 pK
CHROMOSOMES WITH BIO-CHEMISTRY
Where acid group found Acid form = Base form,
C6H14N4O2-Arginine R-NH-C=NH2 = R-NH-C=NH + H = 11.5-12.5 pK
| |
NH2 NH2
Guanidinium = Guanidio
Left side = C6H14N4O2 = 177.5
Guanidio = R-NH-C=NH + H
|
NH2 = 60.25
= a2 - b2 = c2
= a2 (Left side) + b2 (Guanidio) = c2
= a2 (177.5) + b2 (60.25) = c2
= a + b = (31506.25) + b (3630.0625) = c2
= a + b = 35136.3125 = c2
= a + b = 35136.3125 / 187.44 = 187.45
= a + b = 187.45 / 1.5 Optimum pH of stomach pepsin = 124.96
= a + b = 125 / 2.118 Optimum pH of stomach peptide bond = 59
= a + b = 59 = NH-C=NH
|
NH2= 59 = Guanidio at right side
= a + b = 44 = NH-C=NH + H+
|
NH2 = 60.25 = Guanidio at right side
= a + b = 60.25 / 5 hydrogen atoms = 12.05 pK
HUMAN CHROMOSOMES
Guanidio at right side = NH-C=NH + H+
|
NH2 = 60.25
Human chromosomes = 46.25
= a2 + b2 = c2
= a2 (Guanidio) + b2 (chromosomes) = c2
= a2 (60.25) + b2 (46.25) = c2
= a + b = (3630.0625) + b (2139.0625) = c2
= a + b = 5769.125 = c2
= a + b = 5769.125 / 75.95 = 75.95
= a + b = 75.95 – 15.7 (O1) = 60.25
= a + b = 60.25 = NH-C=NH + H+
|
NH2 = 60.25 = base form at right side,
= a + b = 60.25 / 5 hydrogen atoms = 12.05 pK