BIO ALGEBRA OF LIVING ORGANISMS

(Bio Mathematical Lab of Sikander Aqeel) 

CHAPTER [3] PROTEINS  

Proteins  

(8/20/2016) 

Charge and Chemical Properties of Amino acids and Proteins, 

An understanding of protein requires knowledge of the ionizable side chain groups of the common amino acids, these ionizable groups common to proteins and amino acids, the acid form of the respective ionizable groups are on the left of the sum, while the respective properties base are on the right side, characteristic of the acid form is that nitrogen-containing groups are positively charged, whereas the acid forms that contain oxygen and sulfur atoms are natural,   

Where acid group found            Acid form = Base form,  

C3H7NO2S = Cysteine                     R-SH = R-S + H+ = 8.0-9.0 pK 

                                      Thiol = Thiolate    

Left side = C3H7NO2S = 122.75

Thiolate = R-S + H+ = 33.25

  = a2 - b2 = c2 

  = a2 (Left side) + b2 (Thiolate) = c2 

  = a2 (122.75) + b2 (33.25) = c2 

  = a + b = (15067.5625) + b (1105.5625) = c2 

  = a + b = 16173.125 = c2 

  = a + b = 16173.125 / 127.17 = 127.17

  = a + b = 127.17 / 1.5 Optimum pH of stomach pepsin = 84.78

  = a + b = 84.78 / 2.649 Optimum pH of stomach peptide bond = 32

  = a + b = 32 = S Thiolate at right side  

  = a + b = 33.25 = S + H+ = 33.25 = Thiolate at right side  

  = a + b = 33.25 / 4.156 hydrogen atoms = 8.0 pK  

CHROMOSOMES WITH BIO-CHEMISTRY 

Where acid group found            Acid form = Base form,  

C3H7NO2S = Cysteine                     R-SH = R-S + H+ = 8.0-9.0 pK 

                                      Thiol = Thiolate    

Left side = C3H7NO2S = 122.75

Thiolate = R-S + H+ = 33.25

  = a2 - b2 = c2 

  = a2 (Left side) + b2 (Thiolate) = c2 

  = a2 (122.75) + b2 (33.25) = c2 

  = a + b = (15067.5625) + b (1105.5625) = c2 

  = a + b = 16173.125 = c2 

  = a + b = 16173.125 / 127.17 = 127.17

  = a + b = 127.17 / 1.5 Optimum pH of stomach pepsin = 84.78

  = a + b = 84.78 / 2.649 Optimum pH of stomach peptide bond = 32

  = a + b = 32 = S Thiolate at right side  

  = a + b = 44 = S + H+ = 33.25 = Thiolate at right side  

  = a + b = 33.25 / 4.156 hydrogen atoms = 8.0 pK  

HUMAN CHROMOSOMES 

Thiolate = R-S + H+ = 33.25

Human chromosomes = 46.25 

  = a2 + b2 = c2 

  = a2 (Thiolate) + b2 (chromosomes) = c2 

  = a2 (33.25) + b2 (46.25) = c2 

  = a + b = (1105.5625) + b (2139.0625) = c2 

  = a + b = 3244.625 = c2 

  = a + b = 3244.625 / 56.96 = 56.96

  = a + b = 56.96  – 23.71 (H2O + H5) = 33.25

  = a + b = 33.25 = S + H+ = base form at right side, 

  = a + b = 33.25 / 3.694 hydrogen atoms = 9.0 pK