BIO ALGEBRA OF LIVING ORGANISMS

(Bio Mathematical Lab of Sikander Aqeel) 

CHAPTER [3] PROTEINS  

Proteins  

(8/24/2016) 

Charge and Chemical Properties of Amino acids and Proteins, 

An understanding of protein requires knowledge of the ionizable side chain groups of the common amino acids, these ionizable groups common to proteins and amino acids, the acid form of the respective ionizable groups are on the left of the sum, while the respective properties base are on the right side, characteristic of the acid form is that nitrogen-containing groups are positively charged, whereas the acid forms that contain oxygen and sulfur atoms are natural, 

Titration of a Monoamino Dicarboxylic Acid 

A more complecated example of the relationship between molecular charge and pH is the example of Glutamic acid, its ionized forms and titration curve are shown in Glutamic acid, the a-COOH pKa = 2.2, the Y-COOH pka = 4.3, and the a-NH3+ pKa = 9.7, the zwqitterion form is generated after 1.5 equiv of base are sdded to the low pH form, and the isoelectric pH (pI) is calculated from the average of the two pKa values that form the boundaries of the zwitterion form, 

Common Charge Properties of Amino acids and Proteins 

All **ysis of the charge form present in the other common amino acids shows that the relationship found between pH and the respective pI constant for Leucine and Glutamate is perfectly true,   

         2.2 + 4.3

pI = ------------------ = 3.25 

             2        

Leucine = C6H13NO2 = 134.25 m/g

Leucine pH = 5.98  

  = a2 - b2 = c2 

  = a2 (Leucine) + b2 (Leucine pH) = c2 

  = a2 (134.25) + b2 (5.98) = c2 

  = a + b = (18023.0625) + b (35.7604) = c2 

  = a + b = 18058.8229 = c2 

  = a + b = 18058.8229 / 134.38 = 134.38

  = a + b = 134.38 / 2.5 (H2= A//T DNA) = 53.752

  = a + b = 53.752 / 3.75 (H3= C///G DNA) = 14.33 

  = a + b = 14.33 / 2 pH (pepsin enzyme) = 7.165 

  = a + b = 7.165 / 5.98 (Leucine pH) = 1.198

  = a + b = 1.19 % less pH of Leucine = positively charged 

This is at the solution pH less than the pI of amino acid, the amino acid is positively charged,

CHROMOSOMES WITH BIO-CHEMISTRY 

Leucine = C6H13NO2 = 134.25 m/g

Leucine pH = 5.98  

  = a2 + b2 = c2 

  = a2 (Leucine) + b2 (chromosomes) = c2 

  = a2 (134.25) + b2 (46.25) = c2 

  = a + b = (18023.0625) + b (2139.0625) = c2 

  = a + b = 20162.125 = c2 

  = a + b = 20162.125 / 141.99 = 141.99

  = a + b = 141.99 / 2.5 (H2= A//T DNA) = 56.796

  = a + b = 56.796 / 3.75 (H3= C///G DNA) = 15.1456 

  = a + b = 15.1456 / 2 pH (pepsin enzyme) = 7.5728 

  = a + b = 7.5728 / 5.98 (Leucine pH) = 1.26

  = a + b = 1.26 % grater pH of Leucine = negatively charged  

This is at the solution pH less than the pI of amino acid, the amino acid is positively charged, 

At a pH greater then pI, the amino acid is negatively charged 

  = a + b = 1.19 % less pH of Leucine, 

  = a + b = 1.26 % grater pH of Leucine, 

The degree of positive and negative charge is a function of the distance between the pH and the pI value of the amino acids and is calculable for an amino acid by chromosomes of DNA, 

pH > pI, then protein charge negative 

pH < pI, then protein charge positive,