Sikander Aqeel

THE ALCOHOLIC LIVER DISEASE,

Aug 23rd 2016, 11:06 am
Posted by aqeelsika
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(Two Polynucleotide in mathematical machine of Sikander Aqeel) 

WILSON DISEASE 

Lower-than-normal ALP levels 

1 = Hypophosphatasia 

2 = Malnutrition 

3 = Wilson disease 

Wilson disease has a range of clinical manifestations, from an asymptomatic state to fulminate hepatic failure, chronic liver disease with or without cirrhosis, neurologic, and psychiatric manifestations

Consider hepatic Wilson disease in the differential diagnosis of any unexplained chronic liver disease, especially in individuals younger than 40 years. The condition may also manifest as acute hepatitis. Hepatic dysfunction is the presenting feature in more than half of patients. The 3 major patterns of hepatic involvement are as follows: 

(1) chronic active hepatitis, 

(2) cirrhosis, and 

(3) fulminant hepatic failure. The most common initial presentation is cirrhosis. 

 

2 = CIRRHOSIS (8/12/2016) 

Definitions of cirrhosis

noun

A chronic disease of the liver marked by degeneration of cells, inflammation, and fibrous thickening of tissue. It is typically a result of alcoholism or hepatitis.

Chronic viral hepatitis is the main cause of chronic liver disease, cirrhosis and hepatocellular carcinoma throughout the world.

 

ABOUT CHOLESTASIS (8/24/2016) 

Cholestasis means any condition in which bile flow is reduced or stopped. "Chole" refers to bile and "stasis" means "not moving." Bile flow may be blocked inside the liver, outside the liver, or in both places. Symptoms may include:

Jaundice

Dark urine

Pale stool

Easy bleeding

Itching

Ascites 

Chills

Pain from the biliary tract or pancreas

Enlarged gallbladder

Some causes of cholestasis include the following:

Hepatitis

Alcoholic liver disease

Primary biliary cirrhosis

Drug effects

Hormonal changes during pregnancy

A stone in the bile duct

Bile duct narrowing

Bile duct cancer

Pancreatic cancer

Inflammation of the pancreas 

 

NATURAL ALCOHOL 

TERTIARY NATURAL ALCOHOL

The Alcoholic liver disease with Urease and Arginase enzymes of liver, while Tertiary natural Alcohol being use for disease,       

 

Tertiary Alcohol = C4-OH = 65.25 m/g 

Tertiary Alcohol = 65.25 / 100 % = 0.6525

                 = 0.6525 * 322 % = 210

                 = 210 m/g = 322 percent  Alcohol

 

 

Urease enzyme = Liver = 8.0 optimum pH = (substrate = Urea)

Arginase enzyme = Liver = 9.7 optimum pH = (substrate = Arginine amino acids) 

 

Urease + Arginase enzyme = 17.7 optimum pH   

322 % Alcohol = 210 m/g

 

         = a2 + b2 = c2 

         = a2 (322 % Alcohol) + b2 (Urease + Arginase enzyme) = c2  

 

         = a2 210 + b2 17.7 = c2 

 

         = a2 44100 + b2 313.29 = c2 

 

         = a + b = 44413.29 = c2     

         = a + b = 44413.29 / 210.74 = 210.74

 

         = a + b = 210.74 / 2.5 (H2= A//T DNA) = 84.296

         = a + b = 84.296 / 3.75 (H3= C///G DNA) = 22.47

         = a + b = 22.47 * 50 ratio = 1123.5

         = a + b = 1123.5 / 33.51A = 33.52A

         = a + b = 34A = healthy height of helix  

 

        = Alcohol = 34A / 10 mononucleotide = 3.4

        =         = 3.4A healthy distance between two base pair, 

 

For example 

Urease enzyme = Liver = 8.0 optimum pH = (substrate = Urea)

Arginase enzyme = Liver = 9.7 optimum pH = (substrate = Arginine amino acids) 

 

Urease + Arginase enzyme = 17.7 optimum pH   

322 % Alcohol = 210 m/g

 

    = a2 + b2 = c2 

    = a2 (322 %  Alcohol) + b2(Urease + Arginase enzyme) = c2  

 

    = a2 210 + b2 17.7 = c2 

 

    = a2 44100 + b2 313.29 = c2 

 

    = a + b = 44413.29 = c2     

    = a + b = 44413.29 + 20086.71 = 64500 m/g hemoglobin  

    = a + b = 20086.71 =? 

 

 

Liver reduce

    = a + b = 20086.71 / 9.7 pH of arginsea enzymes of liver = 2070.79

    = a + b = 2071 / 7.0 pH of Urease enzymes of Urea = 295.85

    = a + b = 296 / 8.0 pH of Lipase enzymes of pancreas = 37

    = a + b = 37 = 2H2O = two unit water, 

 

So reduce liver need is two unit water for hemoglobin, while natural DNA helix is 34A height and 3.4A distance between two base pairs, and normal natural alcohol occurs 332 % in whole body, to act against the pain of work, or when human start daily work then 332 % natural alcohol becomes active in whole body for finish the pain or fatigue of work,    

 

 

ALP - BLOOD TEST        

Normal Results (ALP) tissues protein

The normal range is 44 to 147 IU/L (international units per liter) 

 

The normal range = 147 IU/L for maximum weight and young age    

The normal range = 44 IU/L for minimum weight and over age  

 

HEALTHY LIVER

OVER ALCOHOL IN ALP BLOOD TEST (LOWER) 

(ALP) tissues protein = 44 * 4.772 (pH of urine microbes) = 210

                      = 210 m/g = 322 % normal Alcohol, 

 

LIVERE  

OVER ALCOHOL IN ALP BLOOD TEST (HIGHER) 

(ALP) tissues protein = 147 * 1.428 (pepsine optimum pH) = 210

                      = 210 m/g = 322 %  normal Alcohol,  

 

 

 

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