Sikander Aqeel

THE ALCOHOLIC LIVER DISEASE,

Sep 5th 2016, 11:17 am
Posted by aqeelsika
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(Two Polynucleotide in mathematical machine of Sikander Aqeel) 

WILSON DISEASE 

Lower-than-normal ALP levels 

1 = Hypophosphatasia 

2 = Malnutrition 

3 = Wilson disease 

Wilson disease has a range of clinical manifestations, from an asymptomatic state to fulminate hepatic failure, chronic liver disease with or without cirrhosis, neurologic, and psychiatric manifestations

Consider hepatic Wilson disease in the differential diagnosis of any unexplained chronic liver disease, especially in individuals younger than 40 years. The condition may also manifest as acute hepatitis. Hepatic dysfunction is the presenting feature in more than half of patients. The 3 major patterns of hepatic involvement are as follows: 

(1) chronic active hepatitis, 

(2) cirrhosis, and 

(3) fulminant hepatic failure. The most common initial presentation is cirrhosis. 

 

2 = CIRRHOSIS  

Definitions of cirrhosis

noun

A chronic disease of the liver marked by degeneration of cells, inflammation, and fibrous thickening of tissue. It is typically a result of alcoholism or hepatitis.

Chronic viral hepatitis is the main cause of chronic liver disease, cirrhosis and hepatocellular carcinoma throughout the world.

 

ABOUT CHOLESTASIS (9/6/2016) 

Cholestasis means any condition in which bile flow is reduced or stopped. "Chole" refers to bile and "stasis" means "not moving." Bile flow may be blocked inside the liver, outside the liver, or in both places. Symptoms may include:

Jaundice

Dark urine

Pale stool

Easy bleeding

Itching

Ascites 

Chills

Pain from the biliary tract or pancreas

Enlarged gallbladder

Some causes of cholestasis include the following:

Hepatitis

Alcoholic liver disease

Primary biliary cirrhosis

Drug effects

Hormonal changes during pregnancy

A stone in the bile duct

Bile duct narrowing

Bile duct cancer

Pancreatic cancer

Inflammation of the pancreas 

 

NATURAL ALCOHOL 

TERTIARY NATURAL ALCOHOL

The Alcoholic liver disease with Urease and Arginase enzymes of liver, while Tertiary natural Alcohol being use for disease,       

 

Tertiary Alcohol = C4-OH = 65.25 m/g 

Tertiary Alcohol = 65.25 / 100 % = 0.6525

                 = 0.6525 * 332.18 % = 216.74

                 = 216.75 m/g = 332.18 percent Alcohol in body 

 

BLOOD SUPPLY TO HEPATIC ARTERY

OXYGENATED BLOOD FLOWS IN FROM THE HEPATIC ARTERY 

The liver holds about one pint (13%) of the body's blood supply at any given moment. The liver consists of 2 main lobes, both of which are made up of 8 segments that consist of 1,000 lobules. These lobules are connected to small ducts that connect with larger ducts to ultimately form the common hepatic duct. The common hepatic duct transports the bile produced by the liver cells to the gallbladder and duodenum (the first part of the small intestine) via the common bile duct. 

 

Lobules of liver = 1000   

332.18 % Alcohol = 216.75 m/g

 

         = a2 + b2 = c2 

         = a2 (332.18 % Alcohol) + b2 (lobules) = c2  

 

         = a2 216.75 + b2 1000 = c2 

 

         = a2 46980.5625 + b2 1000000 = c2 

 

         = a + b = 1046980.5625 = c2     

         = a + b = 1046980.5625 / 1023.22 = 1023.22

 

         = a + b = 1023.22 / 2.5 (H2= A//T DNA) = 409.288

         = a + b = 409.288 / 3.75 (H3= C///G DNA) = 109.14

         = a + b = 109 * 50 ratio = 5450

         = a + b = 5450 / 15.5A (too short height of helix) = 351.61

         = a + b = 351.61 + 1.75 H = 353.36 

         = a + b = 353.36 = yellow hyperlipidemia 

 

15.5A height of helix

So if we shorts to height of helix, then body produces yellow color lipids for Jaundice, or natural alcohol 332.18 + 21.18 (H2O + H2) = 353.36 yellow hyperlipidemia or with presence of excess yellow lipids in blood, and intake of lipids occurs very danger in Jaundice, 

 

Because berberine = strong yellow fluorescence = C20H18NO4 = 336.3612 g/mol 

Strong yellow fluorescence = 336.3612 + 16.99 Oxygen = 353.36 yellow hyperlipidemia 

 

PIECES OF HYPERLIPIDEMIA IN LIVER (9/6/2016) 

Now we are making pieces of hyperlipidemia through the natural healthy 34A and 3.4A helix of DNA, 

 

Sodium bicarbonate or (Bile) = NaHCO3 = 84.25 m/g 

Arginase enzyme of liver = 9.7 pH  

Healthy Helix height = 34A 

Healthy Helix distance between two base pair = 3.4A   

 

         = a2 + b2 = c2 

         = a2 (helix height) + b2 (helix distance two base) = c2  

 

         = a2 34A + b2 3.4A = c2 

 

         = a2 1156 + b2 11.56 = c2 

 

         = a + b = 1167.56 = c2     

         = a + b = 1167.56 / 34.34 = 34.34

 

         = a + b = 34.34 * 2.5 (H2= A//T DNA) = 85.85

         = a + b = 85.85 * 3.75 (H3= C///G DNA) = 321.9375

         = a + b = 321.9375 * 50 ratio = 16096.875 

 

         = a + b = 16096.875 / 84.25 m/g sodium bicarbonate (Bile) = 191.06

         = a + b = 191 / 19.690 (H2O + H) = 9.700  

         = a + b = 9.7 = pH of Arginase enzyme of liver. 

 

If natural healthy helix of DNA becoming (Bile) fluid, then fat going to be divide in small pieces for (Emulsification) of liver, 

 

As a prove the too short and sick helix becoming hyperlipidemia or excess fat and healthy helix of DNA going to do pieces of hyperlipidemia from bile or sodium bicarbonate salt,           

 

 

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