Sikander Aqeel

STONE IN THE BILE DUCT,

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(Two Polynucleotide in mathematical machine of Sikander Aqeel) 

WILSON DISEASE 

Lower-than-normal ALP levels 

1 = Hypophosphatasia 

2 = Malnutrition 

3 = Wilson disease 

 

Wilson disease has a range of clinical manifestations, from an asymptomatic state to fulminate hepatic failure, chronic liver disease with or without cirrhosis, neurologic, and psychiatric manifestations

Consider hepatic Wilson disease in the differential diagnosis of any unexplained chronic liver disease, especially in individuals younger than 40 years. The condition may also manifest as acute hepatitis. Hepatic dysfunction is the presenting feature in more than half of patients. The 3 major patterns of hepatic involvement are as follows: 

(1) chronic active hepatitis, 

(2) cirrhosis, and 

(3) fulminant hepatic failure. The most common initial presentation is cirrhosis. 

 

= CIRRHOSIS  

Definitions of cirrhosis

noun

A chronic disease of the liver marked by degeneration of cells, inflammation, and fibrous thickening of tissue. It is typically a result of alcoholism or hepatitis.

Chronic viral hepatitis is the main cause of chronic liver disease, cirrhosis and hepatocellular carcinoma throughout the world.

 

ABOUT CHOLESTASIS (9/11/2016) 

Cholestasis means any condition in which bile flow is reduced or stopped. "Chole" refers to bile and "stasis" means "not moving." Bile flow may be blocked inside the liver, outside the liver, or in both places. Symptoms may include:

Jaundice

Dark urine

Pale stool

Easy bleeding

Itching

Ascites 

Chills

Pain from the biliary tract or pancreas

Enlarged gallbladder

Some causes of cholestasis include the following:

Hepatitis

Alcoholic liver disease

Primary biliary cirrhosis

Drug effects

Hormonal changes during pregnancy

A stone in the bile duct

Bile duct narrowing

Bile duct cancer

Pancreatic cancer

Inflammation of the pancreas 

 

A STONE IN THE BILE DUCT (9/22/2016) 

The stone in bile duct as hard calcium, Magnesium, and Uric Acid type material, 

 

BILE DUCT COLOR AND CHEMICALS

Glycocholic acid = C26H43NO6 = 465.631 g/mol

Dark Green color = 580 (nm) 

 

         = a2 + b2 = c2 

         = a2 (Glycocholic acid) + b2 (Dark Green color) = c2  

 

         = a2 465.631 g/mol      + b2 580 (nm) = c2 

 

         = a2 216812.228161      + b2 336400 = c2 

 

         = a + b = 553212.228161 = c2     

         = a + b = 553212.228161 / 743.78 = 743.78 

 

         A stone in bile duct

         = a + b = 743.78 / 18.5 (H2O) = 40.20, Calcium as stone in bile duct 

         = a + b = 743.78 / 30.99 (P1) = 24.00, Magnesium as stone in bile duct 

         = a + b = 743.78 / 4.40 pH (of Lipase enzyme) = 169, Uric Acid as stone in bile duct 

 

         B Condition of DNA

         = a + b = 743.78 / 2.5 (H2= A//T DNA) = 297.512

         = a + b = 297.512 / 3.75 (H3= C///G DNA) = 79.33

         = a + b = 79.33 * 50 ratio = 3966.5

 

         = a + b = 3966.5 / 62.98A = 62.98A 

         = a + b = 63A, abnormal height of DNA helix by use of nitrogen acid 

 

         = a + b = 63A / 10 mononucleotide = 6.3 

         = a + b = 6.3A, abnormal distance between two base pair  

 

MUTATION BY 3.7 H2 

DNA 63A height / 34A normal height = 1.85 value of H1 

DNA 63A height / 34A normal height = 1.85 value of H1

                                   = ----------------- + 

                                     3.7 value of H2

 

Micrometer = 10 * 1000 = 10000 

           = 10000 * 24 hours = 240000 

           = 240000 * 3.7 H2 = 888000 

           = 888000, gene of two base pair,  

 

Two base pair = 888000 – 300000 healthy gene of H1 = 588000 

              = 588000 - 300000 healthy gene of H1 = 288000 

              = 288000 gene = heavy mutation in bile duct 

 

Heavy mutation = 288000 gene / 1000 gene = 288 gene second mutation 

               = 288 / 10 micrometer = 28.8 gene first mutation for stone in bile duct, 

 

MUTATION BASE 

4.40 pH (of Lipase enzyme)  

First mutation = 28.8 gene * 4.40 pH = 126.72 

               = 126.72 = Thymine = C5H6N2O2 = 126.11 g mol−1 = (T) 

 

In the first round of replication Uracil select Adenine as the complementary base, in the second round of replication Uracil is replaced by Thymine   

 

TREATMENT

         B Condition of DNA

         C Treatment of bile duct stone

         = a + b = 743.78 / 2.5 (H2= A//T DNA) = 297.512

         = a + b = 297.512 / 3.75 (H3= C///G DNA) = 79.33

         = a + b = 79.33 * 14.572 (N1) treatment = 1155.99 

 

         = a + b = 1156 / 34A = 34A 

         = a + b = 34A, normal height of DNA helix by use of nitrogen salt 

 

         = a + b = 34A / 10 mononucleotide = 3.4 

         = a + b = 3.4A, normal distance between two base pair by use of nitrogen salt 

 

So the bile duct stone increases as Glycocholic acid value increases in 100 % green color of duct, which increase 28.8 genes in DNA helix with Thymine sets,

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