(Bio Mathematical Lab of Sikander Aqeel)
CHAPTER [3] PROTEINS
Proteins
TECHNIQUES UTILIZED TO DETERMINE THE AMINO ACID SEQUENCE OF A PROTEIN
Knowledge of the primary structure (amino acid sequence) of a protein is required for an understanding of the relationship of a protein’s structure to its function on a molecular level,
In the determination of primary structure, first the number of polypeptide chain in the protein must be ascertained, to begin with the protein is denatured, and the treated with a reagent, such as Insulin, that forms a covalent bond with the NH2-termina a-amino groups of each polypeptide chain within the protein the tagged protein is then hydrolyzed to its constituent amino acids, typically condition for complete protein hydrolysis are 6 N HCl at 110 centigrade for 18 to 36 hours, in a sealed tube under vacuum, the vacuum prevents degradation of oxidation sensitive,
PROTEIN HYDROLYSIS (10/14/2016)
Alcohol = OH = 17.25 * 51 amino acids = 879.75
= 879.75 + 6.25 Sikander Aqeel = 886
1 = Hormone Peptide = 886 m/g for 51 amino acids of Insulin
2 = Centigrade = 110
= a2 / b2 = c2
= a2 (Hormone Peptide) / b2 (centigrade) = c2
= a2 (886) / b2 (110) = c2
= a / b = (784996) / b (12100) = c2
= a / b = 64.87 = c2
= a / b = 64.87 - 1.37 H = 63.5
= a / b = 63.5 = (CH2OH)2 glucose level
PROTEIN HYDROLYSIS
1 = Hormone Peptide = 886 m/g for 51 amino acids of Insulin
2 = Centigrade = 110
= a2 + b2 = c2
= a2 (Hormone Peptide) + b2 (centigrade) = c2
= a2 (886) + b2 (110) = c2
= a + b = (784996) + b (12100) = c2
= a + b = 797096 = c2
= a + b = 797096 / 892.80 = 892.80
= a + b = 892.80 / 2.5 (H2= A//T DNA) = 357.12
= a + b = 357.12 / 3.75 (H3= C///G DNA) = 95.232
= a + b = 95.25 + 0.68 = 95.25
= a + b = 95.25 = (CH2OH)3 glucose level
HUMAN CHROMOSOMES
1 = Human Chromosomes = 46.25
2 = Hormone Peptide = 886 m/g for 51 amino acids of Insulin
= a2 + b2 = c2
= a2 (Hormone Peptide) + b2 (Chromosomes) = c2
= a2 (886) + b2 (46.25) = c2
= a + b = (784996) + (2139.0625) = c2
= a + b = 787135.0625 = c2
= a + b = 787135.0625 / 887.20 = 887.21
= a + b = 887.21 / 2.5 (H2= A//T DNA) = 354.884
= a / b = 354.884 / 3.75 (H3= C///G DNA) = 94.63
= a / b = 94.63 + 0.62 = 95.25
= a / b = 95.25 = (CH2OH)3 glucose level
Lowers blood glucose level, promotes glucose storage as glycogen and fat. Fasting decreases insulin production.