Sikander Aqeel

BIO ALGEBRA OF LIVING ORGANISMS

Dec 15th 2016, 11:27 am
Posted by aqeelsika
419 Views

(Bio Mathematical Lab of Sikander Aqeel) 

CHAPTER [3] PROTEINS  

Proteins  

THE PRIMARY STRUCTURE OF INSULIN

A study of the primary structure of the protein hormone insulin elucidates chemical events that occur in the biosynthesis of insulin from precursor forms in the pancreatic islet cells, Insulin is initially produced in a form known as preproinsulin, which is converted to an intermediate size protein proinsulin, in the endoplasmic reticulum by an enzyme-catalyzed hydrolysis of the NH3-terminal 23 amino acids in the preproinsulin,     

 

PRIMARY STRUCTURE OF INSULIN (12/16/2016) 

DNA STRUCTURE 

Preproinsulin by C - Peptide 

B – end of B chain 

Alanine = 90.75 m/g  

Alanine = 90.75 m/g  

Alanine = 90.75 m/g  

Proline = 117.25 m/g 

Aspartic acid = 134.75 m/g 

Proline = 117.25 m/g 

Glycine = 76.25 m/g 

Tryptophan = 207 m/g 

Leucine = 134.25 m/g 

Alanine = 90.75 m/g 

Leucine = 134.25 m/g 

Leucine = 134.25 m/g 

Alanine = 90.75 m/g 

Leucine = 134.25 m/g 

Leucine = 134.25 m/g 

Proline = 117.25 m/g 

Leucine = 134.25 m/g 

Leucine = 134.25 m/g 

Arginine = 177.5 m/g 

Methionine = 151.75 m/g 

Tryptophan = 207 m/g 

Leucine = 134.25 m/g 

Alanine = 90.75 m/g 

Methionine = 151.75 m/g  

Total = 3076.25 amino acids of B chain end 

 

DNA STRUCTURE 

1 = Pancreas = Insulin = 51 amino acids 

2 = end of B chain = 3076.25 m/g 

 

  = a2 + b2 = c2 

  = a2 (end of B chain) / b2 (Insulin) = c2 

  = a2 (3076.25)        / b2 (51) = c2   

 

  = a + b = (9463314.0625) + b (2601) = c2 

  = a + b = 9465915.0625 = c2 

  = a + b = 9465915.0625 / 3076.67 = 3076.67

 

  = a + b = 3076.67 - 135.13 g mol Adenine = 2941.54

  = a + b = 2941.54 / 51 amino acid of Insulin = 57.67

  = a + b = 57.67 + 4.08 (H3) = 61.75

  = a + b = 61.75= (Beginning of COOH and end of NH2 of smaller polypeptide  

 

 

  = a + b = 3076.67 / 2.5 (H2= A//T DNA) = 1230.668

  = a + b = 1230.668 / 3.75 (H3= C///G DNA) = 328.17

  = a + b = 328.17 / 7.4 (pH of blood plasma) = 44.34

  = a + b = 44.34 – 0.34 (H4) = 44

  = a + b = 44 = CO2 energy of insulin chain, end of B chain 

 

 

Carbon dioxide + carboxylic acid + Amide ion = A..    

 

HUMAN CHROMOSOMES 

DNA STRUCTURE 

1 = 20 basic amino acids = 2784.25 mole

2 = Human Chromosomes = 46.25 

 

  = a2 + b2 = c2 

  = a2 (20 basic amino acids) + b2 (Chromosomes) = c2 

  = a2 (2784.25)              + b2 (46.25) = c2 

 

  = a + b = (7752048.0625) + (2139.0625) = c2 

  = a + b = 7754187.125 = c2 

  = a + b = 7754187.125 / 2784.63 = 2784.63 

 

  = a + b = 2784.63 = polypeptide

 

  = a + b = 2784.63 - 135.13 g mol Adenine = 254 mole9.5

  = a + b = 254 mole9.5 / 40 amino acids of polypeptide = 66.2375

  = a + b = 66.23 - 2.73 H2 = 63.5

  = a + b = 63.5 = fructose = CH2OH 

  = a + b = 63.5 = two fructose of smaller polypeptide 

 

 

  = a + b = 2784.63 / 2.5 (H2= A//T DNA) = 1113.852

  = a / b = 1113.852 / 3.75 (H3= C///G DNA) = 297.0272

  = a / b = 297.0272 / 8.7 (pH of blood plasma) = 40.13

  = a + b = 40.13 + 5.12 H4 = 45.25 

  = a + b = 45.25 = COOH carboxylic acid of insulin

 

Fructose + carboxylic acid of insulin = A.. 

 

 

The polypeptide NH2-terminal fragment is apparently necessary to facilitate membarne during its biosynthesis, the proinsulin molecule is then a substrate for a second enzyme which catalyzes the hydrolysis of two intrachain peptide bonds in proinsulin, resulting in the cleavage of a 30 amino acids segment from within the polypeptide chain, the active insulin product of these proteolytic hydrolysis consists of two small polypeptide chain that are covalently held togather by cystine disulfide bonds,   

 

 

 

Bookmark & Share:

Please Like Us
Please Like Us