FUSION REACTION OF SIKANDER AQEEL

FUSION REACTION IS EQUAL TO E = m2c 

If helium mass is 4 and fusion value would be 0.5 then two deuterium and three tritium can be fussed to get 17.09 Mev energy,   

        a2 + b2 = c2  

        a2 (deuterium)2-mass + b2 (tritium)3-mass = c2  

           (1.25)2/1         +    (1.25)3/1   

        a2 (2.5) + b2 (3.75) = c2

        a2 (6.25) + b2 (14.0625) = c2 

        a2 + b2 = 20.3125 = c2 

        a2 + b2 = 20.3125 / 4.5 = 4.5 

        a2 + b2 = 4.5 Helium atom + fusion 

        a2 + b2 = 4 Helium atom mass + fusion 0.5  

ENERGY IN ACT OF FUSION BY C1 

If we divide to light speed or c1 from the time, 2-deuterium, and 3-tritium, then we will be get 17.09 Mev fusion energy, 

Single Light speed meter seconds = 300000000 / 20.3125 = 14769230.76

                                 = 14769231 / 24 hour = 615384.625 

                                 = 615384.625 / 60 minute = 10256.41 

                                 = 10256.41 / 60 seconds = 170.9 

                                 = 170.9 / 10 cm = 17.09 

                                 = 17.09 = Mev fusion energy by deuterium tritium, 

                                 = 17.09 Mev energy = E = m2c,