Sikander Aqeel

BINDING ENERGY PER NUCLEON

Jan 27th 2017, 11:19 am
Posted by aqeelsika
415 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c  

 

        Beryllium = Be9 

        Beryllium = 6.46 binding energy per Nucleon 

        Beryllium = 9.05041 Mass-a.m.u  

 

        a2 + b2 = c2  

        a2 (Nucleon)     +     b2 (Mass-a.m.u) = c2  

        a2 (6.46)        +     b2 (9.05041)   

 

        a2 (41.7316)     + b2 (81.9099211681) = c2

 

        a2 + b2 = 123.64 = c2 

        a2 + b2 = 123.64 / 11.11 = 11.12

        a2 + b2 = 11.12 = Be1 + H2 

        a2 + b2 = 9 Beryllium mass + fusion 2.12

 

ENERGY IN ACT BY C1 

When a mass go into the binding energy per Nucleon form, actually they go back into the past when they were warm in beginning, such as in beginning billions years ago the Beryllium was belong with 0.0031 Nucleon per second, 

 Then =  0.0031 * 100 % changes = 0.31 Nucleon 

      = 0.31 Nucleon * 50 ratio = 15.5 

      = 15.5 - 9.04 Be = 6.46 Nucleon energy of today, and from this reason the hydrogen, deuterium, and tritium past is too long than the all metals,   

 

 In Past Nucleon per second was = 0.0031 * 931 Mev = 2.897 seconds of today,         

 

Light speed meter seconds = 300000000 / 123.64 (m2) = 2426399.22

                          = 2426399.22 / 24 hour = 101099.9675

                          = 101099.9675 / 60 minute = 1684.99

                          = 1684.99 / 2.897 seconds = 581.5

                          = 581.5 / 10 cm = 58.15

                          = 58.15 Mev energy = E = m2c, 

 

                          Packing fraction

                      Sec = 2.897 / 0.1734 (% softness) = 16.7 

                          = 16.7  * 10000 fraction = 167000

                          = 167000 Packing fraction,       

 

 

 

 

 

 

 

 

 

 

 

 

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