ENERGY LAW OF SIKANDER AQEEL = E = m2c
Phosphorus = P31
Phosphorus = 8.48 binding energy per Nucleon
Phosphorus = 31.985363 Mass-a.m.u
a2 + b2 = c2
a2 (Nucleon) + b2 (Mass-a.m.u) = c2
a2 (8.48) + b2 (31.985363)
a2 (71.9104) + b2 (1023.063446241769) = c2
a2 + b2 = 1094.97 = c2
a2 + b2 = 1094.97 / 33.09 = 33.09
a2 + b2 = 33.09 = P + H2
a2 + b2 = 31 Phosphorus mass + fusion H2 = 33.09
Phosphorus Binding energy = 131.44 % * H2 of fusion = 262.88 Mev
When you will catalyst to Phosphorus in 131.44 % size and fuse with H1.25 atom, then Phosphorus will give you 262.88 Mev energy, while 1 Mev = 931
Because
Phosphorus Binding energy = 131.44 / 6 proton of C = 21.90
= 21.90 – 15 proton of Phosphorus = 6.9
= 6.9
Phosphorus = 6.9 * 931 Mev = 6423.9
= 6423.9 / 131.44 (P binding E) = 48.87
= 48.87 – 17.87 (-OH = 17.27) = 31
= 31 Phosphorus = Phosphor alcohol
Phosphor = PH3 = 34.75 + 17.25 –OH = 52 – 49 = H3 reaction
ENERGY IN ACT BY C1
When a mass go into the binding energy per Nucleon form, actually they go back into the past when they were warm in beginning, such as in beginning billions years ago the Phosphorus was belong with 0.000091 Nucleon per second,
In Past Nucleon per second was = 0.000091 * 931 Mev = 0.0851 seconds of today,
Light speed meter seconds = 300000000 / 931 (m2) = 322234.15
= 322234.15 / 24 hour = 13426.42
= 13426.42 / 60 minute = 223.77
= 223.77 / 0.0851 seconds = 2628.8
= 2628.8 / 10 cm = 262.88
= 262.88 Mev energy = E = m2c,
Packing fraction
Sec = 0.0851 * -62.2796 minute = -5.29
= -5.3 * 10000 fraction = -53000
= -53000 packing fraction,
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