Sikander Aqeel

ATMOSPHERE OF LITHIUM ON EARTH

Mar 2nd 2017, 11:21 am
Posted by aqeelsika
441 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c  

 

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

 

        a2 (16)          + b2 (9) = c2

 

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

 

Lithium atmosphere energy = 87 % * H0.57 of fusion = 49.59 hour 

 

                       Because 

                       Hour = 49.59 / 6 proton of C = 8.265-Oxygen

                            = 8.265 – 3 proton of Lithium = 5.265-B

                            = 5.265 = Boron

 

          Lithium = 8.265 * 5.265 = 43.515225

                  = 43.515225 + 43.484775 (Li atmosphere CO2 44) = 87

                  = 87  

 

 Chemical = 87 - 80 (Br) excitable atmosphere of earth = 7 

          = 7 = Lithium 

 

Chemical formula from 49.59 hour atmosphere = LiBr  

                                             = LiBr, lithium bromide

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 95.785 PO4 + H = 87.00

                          = 87.00 = LiBr = E = m2c, 

 

 

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