ATMOSPHERE OF LITHIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Lithium bromide dehydrate,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

        a2 (16)          + b2 (9) = c2

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

Lithium energy atmosphere = 124 % * H0.57 of fusion = 70.68 hour 

                       Because 

                       Hour = 70.68 / 6 proton of C = 11.78-Magnesium

                            = 11.78 – 3 proton of Lithium = 8.78-fluorine

                            = 8.78 = fluorine  

Magnesium = 12 proton 

Fluorine = 9 proton

  Lithium = 8.78 * 11.78 = 103.4284

          = 103.4284 + 20.5716 (Li atmosphere H2O + H2 = 21) = 124

                  = 124  

 Chemical = 124 - 80 (Br) Lose water or moisture atmosphere of earth = 44  

          = 44 – 37 (2H2O) = 7 

          = 7 = Lithium 

Chemical formula from 70.68 hour = LiBr-2H2O  

                                 = LiBr-2H2O, lithium bromide dehydrate

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 67.204 (O4 + H3) = 124

                          = 124 = LiBr-2H2O = E = m2c,