Sikander Aqeel

ATMOSPHERE OF LITHIUM ON EARTH

Mar 6th 2017, 11:29 am
Posted by aqeelsika
429 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Lithium cyanide,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

 

        a2 (16)          + b2 (9) = c2

 

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

 

Lithium energy atmosphere = 33 % * H0.57 of fusion = 18.81 hour 

 

                       Because 

                       Hour = 18.81 / 6 proton of C = 3.135-Lithium

                            = 3.135 – 3 proton of Lithium = 0.135-Hydrogen

                            = 9.825  

 

Lithium = 3 proton 

Hydrogen = 1 proton

 

  Lithium = 3.135 / 0.135 = 23.22 (divided form reason of small hydrogen)

          = 23.22 + 9.78 (Li atmosphere H8 = 10) = 33

          = 33  

 

 Chemical = 33 - 12 (C) Poisonous atmosphere of earth = 21  

          = 21 – 14 (N) = 7 

          = 7 = Lithium 

 

Chemical formula from 18.81 hour = LiCN  

                                 = LiCN, lithium cyanide

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 252.52 (9.26HNC = 252.33) = 33

                          = 33 = LiCN = E = m2c,   

Bookmark & Share:

Please Like Us
Please Like Us