ATMOSPHERE OF LITHIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Lithium ethoxide,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

        a2 (16)          + b2 (9) = c2

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

Lithium energy atmosphere = 53.25 % * H0.57 of fusion = 30.3525 hour 

                       Because 

                       Hour = 30.3525 / 6 proton of C = 5.05875-Lithium

                            = 5.05875 – 3 proton of Lithium = 2.05875-Helium

                            = 2.05875  

Boron = 5 proton 

Helium = 2 proton

  Lithium = 2.05875 * 5.05875 = 10.4147015625 

          = 10.4147015625 + 42.8352984375 (LiH3O2 = 42.75) = 53.25

          = 53.25  

 Chemical = 53.25 - 16 (O1) oxides atmosphere of earth = 37.25   

          = 37.25 – 6.25 (H5) = 31 

          = 31 – 24 (C2) = 7 

          = 7 = Lithium 

Chemical formula from 30.3525 hour = LiC2H5O  

                                   = LiC2H5O, lithium ethoxide          

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 156.49 (8.45H2O = 156.325) = 53.25

                          = 53.25 = LiC2H5O = E = m2c,