Sikander Aqeel

ATMOSPHERE OF LITHIUM ON EARTH

Mar 8th 2017, 11:26 am
Posted by aqeelsika
432 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Lithium fluoride,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

 

        a2 (16)          + b2 (9) = c2

 

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

 

Lithium energy atmosphere = 26 % * H0.57 of fusion = 45.614 hour 

 

                       Because 

                       Hour = 45.614 / 6 proton of C = 7.60-Oxygen

                            = 7.60 – 3 proton of Lithium = 4.6-Boron

                            = 4.6

 

Boron = 5 proton 

Oxygen = 8 proton

 

  Lithium = 4.6 * 7.60 = 34.96 H2O2

          = 34.96 - 8.96 (H7 = 8.75) = 26

          = 26

 

 Chemical = 26 - 19 (F) weak poisonous acid atmosphere of earth = 7   

          = 7 = Li = Lithium 

 

Chemical formula from 45.614 hour = LiF  

                                  = LiF, lithium fluoride          

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 320.51 (12-LiF = 312) = 26

                          = 26 = LiF = E = m2c,   

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