Sikander Aqeel

ATMOSPHERE OF LITHIUM ON EARTH

Mar 9th 2017, 11:28 am
Posted by aqeelsika
415 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Lithium hydrogen sulfate,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

 

        a2 (16)          + b2 (9) = c2

 

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

 

Lithium energy atmosphere = 104.25 % * H0.57 of fusion = 59.4225 hour 

 

                       Because 

                       Hour = 59.4225 / 6 proton of C = 9.90375-Neon

                            = 9.90375 – 3 proton of Lithium = 6.90375-N

                            = 6.90375

 

Neon = 10 proton 

Nitrogen = 7 proton

 

  Lithium = 9.90375 * 6.90375 = 68.3730140625

          = 68.3730140625 + 35.8769859375 (H2O2 + H = 35.75) = 104.25

          = 104.25

 

 Chemical = 104.25 - 32 (S) sea salt atmosphere of earth = 72.25 

          = 72.25 – 64 (O4) = 8.25 

          = 8.25 – 1.25 (H) = 7   

          = 7 = Li = Lithium 

 

Chemical formula from 59.4225 hour = LiHSO4  

                                   = LiHSO4, lithium hydrogen sulfate 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 79.93 (4H2O + H5 = 80.25) = 104.25

                          = 104.25 = LiHSO4 = E = m2c,    

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