ATMOSPHERE OF LITHIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Lithium Iodate,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

        a2 (16)          + b2 (9) = c2

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

Lithium energy atmosphere = 182 % * H0.57 of fusion = 103.74 hour 

                       Because 

                       Hour = 103.74 / 6 proton of C = 17.29-Chlorine

                            = 17.29 – 3 proton of Lithium = 14.29-Silicon

                            = 6.90375

Chlorine = 17 proton 

Silicon = 14 proton

  Lithium = 17.29 * 14.29 = 247.0741

          = 247.0741 + 65.0741 (2O2 + H = 65.25) = 182

          = 182

 Chemical = 182 - 127 (I) salted atmosphere of earth = 55

          = 55 – 48 (O3) = 7

          = 7 = Li = Lithium 

Chemical formula from 103.74 hour = LiIO3  

                                  = LiIO3, lithium Iodate 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 45.78 (COOH + 0.53 = 45.78) = 182

                          = 182 = LiIO3 = E = m2c,