Sikander Aqeel

ATMOSPHERE OF LITHIUM ON EARTH

Mar 11th 2017, 11:31 am
Posted by aqeelsika
445 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Sodium lithium,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

 

        a2 (16)          + b2 (9) = c2

 

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

 

Lithium energy atmosphere = 30 % * H0.57 of fusion = 52.631 hour 

 

                       Because 

                       Hour = 52.631 / 6 proton of C = 8.77-Fluorine

                            = 8.77 – 3 proton of Lithium = 5.77-Carbon

                            = 6.90375

 

Fluorine = 9 proton 

Carbon = 6 proton

 

  Lithium = 5.77 * 8.77 = 50.6029

          = 50.6029 + 20.6029 (H2O + H2 = 21) = 30

          = 30

 

 Chemical = 30 - 23 (Na) yellow flame atmosphere of earth = 7

          = 7 = Li = Lithium 

 

Chemical formula from 52.631 hour = LiNa  

                                  = LiNa, sodium lithium 

 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 277.777% (Soft waxy) = 30

                          = 30 = LiNa = E = m2c,    

 

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