ATMOSPHERE OF LITHIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Lithium nitrate,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

        a2 (16)          + b2 (9) = c2

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

Lithium energy atmosphere = 69 % * H0.57 of fusion = 121.052 hour 

                       Because 

                       Hour = 121.052 / 6 proton of C = 20.17-Calcium

                            = 20.17 – 3 proton of Lithium = 17.17-Chlorine

                            = 17.17

Calcium = 20 proton 

Chlorine = 17 proton

  Lithium = 20.17 * 17.17 = 346.3189

          = 346.3189 + 277.3189% (9.24-NO = 277.5) = 69

          = 69

 Chemical = 69 - 14 (N) Organic atmosphere of earth = 55

          = 55 – 48 (O3) = 7

          = 7 = Li = Lithium 

Chemical formula from 121.052 hour = LiNO3  

                                   = LiNO3, lithium nitrate 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 213.67% (7.12-NO = 213.6) = 69

                          = 69 = LiNO3 = E = m2c,