Sikander Aqeel

ATMOSPHERE OF LITHIUM ON EARTH

Mar 16th 2017, 11:51 am
Posted by aqeelsika
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ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Lithium chromate,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

 

        a2 (16)          + b2 (9) = c2

 

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

 

Lithium energy atmosphere = 130 % * H0.57 of fusion = 74.1 hour 

 

                       Because 

                       Hour = 74.1 / 6 proton of C = 12.35-Magnesium

                            = 12.35 – 3 proton of Lithium = 9.35-Fluorine 

                            = 9.35

 

Magnesium = 12 proton 

Fluorine  = 9 proton

 

  Lithium = 12.35 * 9.35 = 115.4725

          = 115.4725 + 14.5275% (N1 + H0.5 = 14.625) = 130

          = 130

 

 Chemical = 130 - 52 (Cr) salt or ester atmosphere of earth = 78

          = 78 – 64 (O4) = 14

          = 14 = Li2 = Lithium 

 

Chemical formula from 74.1 hour = Li2CrO4  

                                 = Li2CrO4, lithium chromate 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 64.1025% (2O2 = 64) = 130

                          = 130 = Li2CrO4 = E = m2c,     

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