Sikander Aqeel

ATMOSPHERE OF LITHIUM ON EARTH

Mar 17th 2017, 11:46 am
Posted by aqeelsika
458 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Lithium dichromate,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

 

        a2 (16)          + b2 (9) = c2

 

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

 

Lithium energy atmosphere = 230 % * H0.57 of fusion = 131.1 hour 

 

                       Because 

                       Hour = 131.1 / 6 proton of C = 21.85-Titanium

                            = 21.85 – 3 proton of Lithium = 18.85-Potassium

                            = 9.35

 

Titanium = 22 proton 

Potassium  = 19 proton

 

  Lithium = 21.85 * 18.85 = 411.8725

          = 411.8725 - 181.8725% (2Li + 4O + 2Cr = 182) = 230

          = 230

 

 Chemical = 230 - 104 (Cr2) dichromate atmosphere of earth = 126

          = 126 – 112 (O7) = 14

          = 14 = Li2 = Lithium 

 

Chemical formula from 131.1 hour = Li2Cr2O7  

                                 = Li2Cr2O7, lithium dichromate 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 36.23% (O2 + H4 = 37) = 230

                          = 230 = Li2Cr2O7 = E = m2c,     

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