HEMORRHAGIC DISEASE
SYNTHESIS OF UMBILICAL CORD
ENZYME + FIBRINOGEN + PROTHROMBIN
Vitamin K deficiency gives rise to abnormal prothrombin levels; thus, prothrombin does not effectively participate in blood clot formation. As noted above, vitamin K undergoes posttranslational carboxylation of glutamic acid resides on the amino-terminal part of the vitamin K-dependent proteins,
1 = Prothrombin = a protein in blood plasma that is the inactive precursor of thrombin,
2 = thrombin = an enzyme that acts on fibrinogen in blood causing it to clot,
1 = Prothrombin or glycoprotein = 72000 molar weight
2 = enzyme + fibrinogen = 341000 molar weight
ANSWER OF DISORDER
Healthy disorders
Vitamin-K = Phylloquinone = 450.7 m/g fat,
A = Prothrombin = 72000 molar weight
B = enzyme + fibrinogen = 341000 molar weight
A = Prothrombin = 72000 / 268.32 = 268.33
B = enzyme + fibrinogen = 341000 / 583.95 = 583.95
ANSWER OF DISORDER
Too Sick disorders
FORMULA TO FIND OUT MEDICINE OF DISEASES
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HEMORRHAGIC DISEASE
SYNTHESIS OF UMBILICAL CORD
ENZYME + FIBRINOGEN + PROTHROMBIN
Enzyme + Fibrinogen = 583.95 + 583.95 = 1167.9
Prothrombin = 268.32 + 268.32 = 536.64
Blood = anemia
a2 + b2 = c2
a2 (Enzyme + Fibrinogen) + b2 (Prothrombin) = c2
a2 (1167.9) + b2 (536.64)
a2 (1363990.41) + b2 (287982.4896) = c2
a2 + b2 = 1651972.8996 = c2
TRANSCRIPTION
= a2 + b2 = 1651972.8996 = transcription
= a2 + b2 = 1651972.8996 * 61 Carbohydrate = 100770346.8756
= a2 + b2 = 100770346.8756 / 112.0868 Uracil = 899038.48
= a2 + b2 = 899038.48 = Two helix of DNA
Uracil + Cytosine = Pyrimidine
Two helix of DNA = 899038.48 / 37 C human temperature = 24298.33
= 24298.33 / 183 glucose = 132.77
= 132.77 + 16.48 (O1) = 149.25
= 149.25 m/l = Glutamic acid
Vitamin K undergoes posttranslational carboxylation of glutamic acid resides on the amino-terminal part of the vitamin K-dependent proteins,
BEGINNER TRANSCRIPTION OF RNA
= a2 + b2 = 899038.48 = beginner transcription of RNA
= a2 + b2 = 899038.48 * 347.5 Sucrose = 312415871.8
= a2 + b2 = 312415871.8 / 135.13 Adenine = 2311965.30
= a2 + b2 = 2311965.30
Adenine + Guanine = Purine
BEGINNER TRANSCRIPTION OF RNA
Transcription of RNA = 2311965.30 / 511 ATP = 4524.39
= 4524.39 + 0.61 () = 4525
= 4525 g/mol = (COOH)- 100 of DNA
Carboxyl group occurs too much prepared of mRNA, tRNA, rRNA,
AMINO ACIDS OF mRNA
= a2 + b2 = 2311965.30 / 1076.26 (A-T=C-G)2 + N2 + H = 1076.19) = 2148.14
= a2 + b2 = 2148.14 = (Polymerase enzyme of RNA)
= a2 + b2 = 2148.14 * 1.2961 (H) = 2784.21
= a2 + b2 = 2784.25 = 20 amino acids of mRNA from Polymerase enzyme
tRNA FROM CYTOPLASM
= a2 + b2 = 2311965.30 * 7.4 pH blood plasma = 17108543.22
= a2 + b2 = 17108543.22 / 40 different cytoplasm in cell = 427713.58
= a2 + b2 = 427713.58 / 157.25 (Histidine) = 2719.95(amino molecules)
= a2 + b2 = 2719.95 - 1046.94 (A-T=C-G) 2 DNA = 1046.94) = 1673.01
= a2 + b2 = 1673.01 - 1046.94 (A-T=C-G) 2 RNA = 1046.94) = 626.07
= a2 + b2 = 626.07 - 117.25 (Proline) = 508.82 or 511
= a2 + b2 = 511 (ATP) energy from normal Enzyme + Fibrinogen + Prothrombin level,
Here (A-T=C-G) 2 = two helix = 511 ATP, if answer comes (A-T=C-G) 3 or 5 then it will be wrong,
= a2 + b2 = 427713.58 = tRNA, mRNA, rRNA from process of cytoplasm
MESSENGER mRNA
= a2 + b2 = 427713.58 / 46.25 chromosomes = 9247.86
= a2 + b2 = 9247.86 information for the ribosomal (messenger mRNA)
INFORMATION OF MESSENGER = 9247.86
= a2 + b2 = 9247.86 * 149.25 g/mol (Gln) = 1380243.105
= a2 + b2 = 1380243.105 / 495.73% nucleated amino-acids move RNA = 2784.32
= a2 + b2 = 2784.25 = 20 amino acids of polypeptide
= a2 + b2 = 2784.25 * 495.73 Mononucleotide = 1380236.2525
= a2 + b2 = 1380236.2525 = molecular weight from 495.73 Mononucleotide
DAILY DIET
= a2 + b2 = 1380236.2525 / 5 (H3 + H2 of DNA) = 276047.2505
= a2 + b2 = 276047.2505 - 36,000 pepsin = 240047.2505
= a2 + b2 = 240047.2505 - 43,000 Albumin = 197047.2505
= a2 + b2 = 197047.2505 - 98,000 Casein = 99047.2505
= a2 + b2 = 99047.2505 - 24000 Trypsinogen = 75047.2505
= a2 + b2 = 75047.2505 - 3047.2505 Polypeptide = 72000
= a2 + b2 = 72000 m/g = Prothrombin or glycoprotein of Umbilical cord,
5 (H3 + H2 of DNA) = (A-T=C-G)
PROTEIN
= a2 + b2 = 1380236.2525 * 23 pair chromosomes cell environment = 31745433.8075
= a2 + b2 = 31745433.8075 + 462.25 (Leucine + Gln + Purine) = 31745896.0575
= a2 + b2 = 31745896.0575 m/g = protein from Enzyme + Fibrinogen + Prothrombin for Vitamin-K,
Total protein = 31745896.0575 / 64500 main hemoglobin = 492.18
= 492.18 / 22.18 times protein = 22.19 times Enzyme + Fibrinogen + Prothrombin for Vitamin-K, and we has already 495.73 phosphoric Mononucleotide for RNA DNA;
SYNTHESIS OF UMBILICAL CORD
Formula of medicines
Fibrinogen + Prothrombin = 22.18 times protein = 22.19 times Enzyme + Fibrinogen + Prothrombin, 495.73 phosphoric Mononucleotide, linked proteins are Pepsin, Albumin, Casein, and Trypsinogen, (A-T=C-G)2 DNA and (A-T=C-G)2 RNA, while 100 carboxyl groups, and Glutamic acid or Vitamin K undergoes posttranslational carboxylation of glutamic acid resides on the amino-terminal part of the vitamin K-dependent proteins, or through this process the deficiency is not of Vitamin-k
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