Sikander Aqeel

ATMOSPHERE OF LITHIUM ON EARTH

Mar 20th 2017, 11:28 am
Posted by aqeelsika
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ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Lithium metaniobate,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

 

        a2 (16)          + b2 (9) = c2

 

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

 

Lithium energy atmosphere = 155 % * H0.57 of fusion = 88.35 hour 

 

                       Because 

                       Hour = 88.35 / 6 proton of C = 14.725-Silicon

                            = 14.725– 3 proton of Lithium = 11.725-Magnesium

 

Silicon = 14 proton 

Magnesium = 12 proton

 

  Lithium = 14.725 * 11.725 = 172.650625

          = 172.650625 - 17.650625% (-OH = 17.25) = 155

          = 155

 

 Chemical = 155 - 93 (Nb) soft gray atmosphere of earth = 62

          = 62 – 48 (O3) = 14

          = 14 = Li2 = Lithium 

 

Chemical formula from 88.35 hour = Li2NbO3  

                                 = Li2NbO3, lithium metaniobate 

 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 53.763% (Li2C2O = 54) = 155

                          = 155 = Li2NbO3 = E = m2c,     

 

 

 

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