Sikander Aqeel

ATMOSPHERE OF LITHIUM ON EARTH

Mar 21st 2017, 11:19 am
Posted by aqeelsika
428 Views

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Lithium sulfate,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

 

        a2 (16)          + b2 (9) = c2

 

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

 

Lithium energy atmosphere = 110 % * H0.57 of fusion = 62.7 hour 

 

                       Because 

                       Hour = 62.7 / 6 proton of C = 10.45-Sodium

                            = 10.45 – 3 proton of Lithium = 7.45-Oxygen

 

Sodium = 11 proton 

Oxygen = 8 proton

 

  Lithium = 10.45 * 7.45 = 77.8525

          = 77.8525 + 32.1475% (O2 = 32) = 110

          = 110

 

 Chemical = 110 - 32 (S) Tasteless odorless atmosphere of earth = 78

          = 78 – 64 (O4) = 14

          = 14 = Li2 = Lithium 

 

Chemical formula from 62.7 hour = Li2SO4  

                                = Li2SO4, lithium sulfate 

 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 75.7575% (S+CO2 = 76) = 110

                          = 110 = Li2SO4 = E = m2c,     

 

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