ATMOSPHERE OF LITHIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Lithium selenite,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

        a2 (16)          + b2 (9) = c2

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

Lithium energy atmosphere = 141 % * H0.57 of fusion = 80.37 hour 

                       Because 

                       Hour = 80.37 / 6 proton of C = 13.395-Aluminum

                            = 13.395 – 3 proton of Lithium = 10.395-Neon

Aluminum = 13 proton 

Neon = 10 proton

  Lithium = 13.395 * 10.395 = 139.241025

          = 139.241025 + 1.758975% (H = 1.25) = 141

          = 141

 Chemical = 141 - 79 (Se) Photocells atmosphere of earth = 62

          = 62 – 48 (O3) = 14

          = 14 = Li2 = Lithium 

Chemical formula from 80.37 hour = Li2SeO3  

                                 = Li2SeO3, lithium selenite 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 59.1016% (Li2 + COOH = 59.25) = 141

                          = 141 = Li2SeO3 = E = m2c,