ATMOSPHERE OF LITHIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Lithium selenate,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

        a2 (16)          + b2 (9) = c2

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

Lithium energy atmosphere = 157 % * H0.57 of fusion = 89.49 hour 

                       Because 

                       Hour = 89.49 / 6 proton of C = 14.915-Phosphorus

                            = 14.915 – 3 proton of Lithium = 11.915-Magnesium

Phosphorus = 15 proton 

Magnesium = 12 proton

  Lithium = 14.915 * 11.915 = 177.712225

          = 177.712225 - 20.712225% (H2O + H2 = 21) = 157

          = 157

 Chemical = 157 - 79 (Se) selenate atmosphere of earth = 78

          = 78 – 64 (O4) = 14

          = 14 = Li2 = Lithium 

Chemical formula from 89.49 hour = Li2SeO4  

                                 = Li2SeO4, lithium selenate 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 53.07853% (H6 + COOH = 52.75) = 157

                          = 157 = Li2SeO4 = E = m2c,