ATMOSPHERE OF LITHIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Lithium metasilicate or lithium orthosilicate,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

        a2 (16)          + b2 (9) = c2

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

Lithium energy atmosphere = 90 % * H0.57 of fusion = 51.3 hour 

                       Because 

                       Hour = 51.3 / 6 proton of C = 8.55-Fluorine

                            = 8.55 – 3 proton of Lithium = 5.55-Carbon

Fluorine = 9 proton 

Carbon = 6 proton

  Lithium = 8.55 * 5.55 = 94.905

          = 94.905 - 4.905% (H4 = 5) = 90

          = 90

 Chemical = 90 - 28 (Si) Electronic atmosphere of earth = 62

          = 62 – 48 (O3) = 14

          = 14 = Li2 = Lithium 

Chemical formula from 51.3 hour = Li2SiO3  

                                = Li2SiO3, lithium metasilicate or lithium orthosilicate 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 92.59255% (Li2SiO3 + H2= 92.5) = 90

                          = 90 = Li2SiO3 = E = m2c,