ATMOSPHERE OF LITHIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Lithium metasilicate or lithium orthosilicate,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

        a2 (16)          + b2 (9) = c2

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

Lithium energy atmosphere = 110 % * H0.57 of fusion = 62.7 hour 

                       Because 

                       Hour = 62.7 / 6 proton of C = 10.45-Sodium

                            = 10.45 – 3 proton of Lithium = 7.45-Oxygen

Sodium = 11 proton 

Oxygen = 8 proton

  Lithium = 10.45 * 7.45 = 55.5025

          = 55.5025 - 54.4975% (O4 + H5 = 54.25) = 110

          = 110

 Chemical = 110 - 48 (Te) strong light weightier atmosphere of earth = 62

          = 62 – 48 (O3) = 14

          = 14 = Li2 = Lithium 

Chemical formula from 62.7 hour = Li2TeO3  

                                = Li2TeO3, lithium tellurite

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 75.75754% (Li4Te = 76) = 110

                          = 110 = Li2TeO3 = E = m2c,