HEMORRHAGIC DISEASE
SYNTHESIS OF UMBILICAL CORD
INTESTINAL ANTIBODIES
Preterm infants who are receiving total parenteral nutrition (TPN) are not at risk because they are receiving vitamin K via the multivitamin additive to the TPN. Special consideration is needed for very low birth weight infants whose intestinal tract bacterial flora is altered because of multiple courses of broad-spectrum antimicrobials. Once preterm infants are weaned off of TPN, they may develop vitamin K deficiency if they are exclusively fed ** milk,
1 = Antimicrobials = Antibody = serum albumin = 68500 molar weight
2 = Microorganisms = 1/10,0000 size
1 = Antibody = serum albumin = 68500 molar weight
2 = Microorganisms = 1/10,0000 size
1 = Antibody = serum albumin = 68500 / 261.72 = 261.73
2 = Microorganisms = 1/10,0000 / 316.22 = 316.23
ANSWER OF DISORDER
Healthy disorders
Vitamin-K = Phylloquinone = 450.7 m/g fat,
1 = Antibody = serum albumin = 68500 / 261.72 = 261.73
2 = Microorganisms = 1/10,0000 / 316.22 = 316.23
A = Antibody = serum albumin = 261.72 algebric
B = Microorganisms = 316.23 algebric
Total = 577.95
Total = 577.95 – 523.74 (A-T=C-G)2 = 54.21
= 54.21 antiOxidants (H2O2 + H2O + H = 54.25)
ANSWER OF DISORDER
Too Sick disorders
FORMULA TO FIND OUT MEDICINE OF DISEASES
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HEMORRHAGIC DISEASE
SYNTHESIS OF UMBILICAL CORD
INTESTINAL ANTIBODIES
Serum albumin = 261.72 + 261.72 = 523.44
Microorganisms = 316.23 + 316.23 = 632.46
Blood = anemia
a2 + b2 = c2
a2 (Microorganisms) + b2 (Serum albumin) = c2
a2 (632.46) + b2 (523.44)
a2 (400005.6516) + b2 (273989.4336) = c2
a2 + b2 = 673995.0852 = c2
TRANSCRIPTION
= a2 + b2 = 673995.0852 = transcription
= a2 + b2 = 673995.0852 * 61 Carbohydrate = 41113700.1972
= a2 + b2 = 41113700.1972 / 112.0868 Uracil = 366802.33
= a2 + b2 = 366802.33 = Two helix of DNA
Uracil + Cytosine = Pyrimidine
Two helix of DNA = 366802.33 / 37 C human temperature = 9913.57
= 9913.57 / 183 glucose = 54.17
= 54.17 = antiOxidants (H2O2 + H2O + H = 54.25),
BEGINNER TRANSCRIPTION OF RNA
= a2 + b2 = 366802.33 = beginner transcription of RNA
= a2 + b2 = 366802.33 * 347.5 Sucrose = 127463809.675
= a2 + b2 = 127463809.675 / 135.13 Adenine = 943268.03
= a2 + b2 = 943268.03
Adenine + Guanine = Purine
BEGINNER TRANSCRIPTION OF RNA
Transcription of RNA = 943268.03 / 511 ATP = 1845.92
= 1845.92 + 9.33 (H8) = 1855.25
= 1855.25 g/mol = (COOH)- 41 of DNA
Carboxyl group occurs too much prepared of mRNA, tRNA, rRNA,
AMINO ACIDS OF mRNA
= a2 + b2 = 943268.03 / 439.10 (4H3PO4 + CO2 = 439) = 2148.18
= a2 + b2 = 2148.14 = (Polymerase enzyme of RNA)
= a2 + b2 = 2148.14 * 1.2961 (H) = 2784.21
= a2 + b2 = 2784.25 = 20 amino acids of mRNA from Polymerase enzyme
So four phosphate with carbon dioxide from reason of antibodies,
tRNA FROM CYTOPLASM
= a2 + b2 = 943268.03 * 7.4 pH blood plasma = 6980183.422
= a2 + b2 = 6980183.422 / 40 different cytoplasm in cell = 174504.58
= a2 + b2 = 174504.58 / 157.25 (Histidine) = 1109.72(amino molecules)
= a2 + b2 = 1109.72 – 1046.94 (A-T=C-G)2 = 62.78
= a2 + b2 = 62.78 + 97.72 (H2PO4) = 160.5
= a2 + b2 = 160.5 = (ADP) energy from Microorganisms + Serum albumin,
= a2 + b2 = 174504.58 = tRNA, mRNA, rRNA from process of cytoplasm
MESSENGER mRNA
= a2 + b2 = 174504.58 / 46.25 chromosomes = 3773.07
= a2 + b2 = 3773.07 information for the ribosomal (messenger mRNA)
INFORMATION OF MESSENGER = 3773.07
= a2 + b2 = 3773.07 * 149.25 g/mol (Gln) = 563130.6975
= a2 + b2 = 563130.6975 / 202.25% nucleated amino-acids move RNA = 2784.33
= a2 + b2 = 2784.25 = 20 amino acids of polypeptide
= a2 + b2 = 2784.25 * 202.25 Mononucleotide = 563114.5625
= a2 + b2 = 563114.5625 = molecular weight from 202.25 Mononucleotide
DAILY DIET
= a2 + b2 = 563114.5625 / 5 (H3 + H2 of DNA) = 112622.9125
= a2 + b2 = 112622.9125 + 36000 pepsin = 76622.9125
= a2 + b2 = 76622.9125 - 8122.9125 polypeptide = 68500
= a2 + b2 = 68500 = serum albumin of antibodies,
5 (H3 + H2 of DNA) = (A-T=C-G)
PROTEIN
= a2 + b2 = 563114.5625 * 23 pair chromosomes cell environment = 12951634.9375
= a2 + b2 = 12951634.9375 + 462.25 (Leucine + Gln + Purine) = 12952097.1875
= a2 + b2 = 12952097.1875 m/g = protein from Microorganisms + Serum albumin,
Total protein = 12952097.1875 / 64500 main hemoglobin = 200.80
= 200.80 / 14.17 times protein = 14.17 times vitamin-k from Microorganisms + Serum albumin, and we have already 202.25 phosphoric Mononucleotide for RNA DNA;
SYNTHESIS OF UMBILICAL CORD
Formula of medicines
Microorganisms + Serum albumin = vitamin-K from presence of microorganism, With components of an emission wave or bacterial flora,
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