ATMOSPHERE OF LITHIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Lithium metasilicate or lithium orthosilicate,  

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

        a2 (16)          + b2 (9) = c2

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

Lithium energy atmosphere = 126 % * H0.57 of fusion = 71.82 hour 

                       Because 

                       Hour = 71.82 / 6 proton of C = 11.97-Magnassium 

                            = 11.97 – 3 proton of Lithium = 8.97-Fluorine

Magnesium  = 12 proton  

Fluorine = 9 proton

  Lithium = 11.97 * 8.97 = 107.3709

          = 107.3709 - 18.6291% (H2O = 18.5) = 126

          = 126

 Chemical = 126 - 48 (Te) strong light weightier atmosphere of earth = 78

          = 78 – 64 (O4) = 14

          = 14 = Li2 = Lithium 

Chemical formula from 71.82 hour = Li2TeO4  

                                = Li2TeO4, lithium tellurate 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 66.1375% (Li2TeH3 = 65.75) = 126

                          = 126 = Li2TeO4 = E = m2c,