Sikander Aqeel

ATMOSPHERE OF LITHIUM ON EARTH

Mar 28th 2017, 11:25 am
Posted by aqeelsika
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ENERGY LAW OF SIKANDER AQEEL = E = m2c 

 

Lithium metatitanate 

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

 

        a2 (16)          + b2 (9) = c2

 

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

 

Lithium energy atmosphere = 266 % * H0.57 of fusion = 151.62 hour 

 

                       Because 

                       Hour = 151.62 / 6 proton of C = 25.27-Manganese  

                            = 25.27 – 3 proton of Lithium = 22.27-Titanium

 

Manganese  = 25 proton  

Titanium = 22 proton

 

  Lithium = 25.27 * 22.27 = 562.7629

          = 562.7629 - 296.7629% (Li4 + Ti + O4 = 296) = 266

          = 266

 

 Chemical = 266 - 204 (Ti) Soft gray atmosphere of earth = 62

          = 62 – 48 (O3) = 14

          = 14 = Li2 = Lithium 

 

Chemical formula from 151.62 hour = Li2TiO3  

                                  = Li2TiO3, lithium metatitanate 

 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 31.328% (Li4 + H3 = 31.75) = 266

                          = 266 = Li2TiO3 = E = m2c,     

 

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