ATMOSPHERE OF LITHIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Lithium orthotungstate = a salt of tungsten acid

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

        a2 (16)          + b2 (9) = c2

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

Lithium energy atmosphere = 262 % * H0.57 of fusion = 149.34 hour 

                       Because 

                       Hour = 149.34 / 6 proton of C = 24.89-Manganese  

                            = 24.89 – 3 proton of Lithium = 21.89-Titanium

Manganese  = 25 proton  

Titanium = 22 proton

  Lithium = 24.89* 21.89 = 544.8421

          = 544.8421 - 282.8421% (Li4 + W + O4 + H5 = 282.25) = 262

          = 262

 Chemical = 262 - 184 (W) Electrical application atmosphere of earth = 78

          = 78 – 64 (O4) = 14

          = 14 = Li2 = Lithium 

Chemical formula from 149.34 hours = Li2WO4  

                                   = Li2WO4, lithium orthotungstate 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 31.8066% (Li4 + H3 = 31.75) = 262

                          = 262 = Li2WO4 = E = m2c,