ATMOSPHERE OF LITHIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Lithium metazirconate 

        Lithium = Li-7  

        Lithium = 7 

        Lithium = 3 proton 

        Lithium = 4 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (4)           +     b2 (3)   

        a2 (16)          + b2 (9) = c2

        a2 + b2 = 25 = c2 

        a2 + b2 = 25 / 7-Li = 3.57

        a2 + b2 = 3.57 = 3 Li proton + H0.57

Lithium energy atmosphere = 153 % * H0.57 of fusion = 87.21 hour 

                       Because 

                       Hour = 87.21 / 6 proton of C = 14.535-Phosphorus  

                            = 14.535 – 3 proton of Lithium = 11.535-Magnesium

Phosphorus  = 15 proton  

           Magnesium = 12 proton

  Lithium = 14.535 * 11.535 = 167.661225

          = 167.661225 - 14.661225% (Li2 = 14) = 153

          = 153

 Chemical = 153 - 91 (Zr) Lustrous gray atmosphere of earth = 62

          = 62 – 48 (O3) = 14

          = 14 = Li2 = Lithium 

Chemical formula from 87.21 hours = Li2ZrO3  

                                  = Li2ZrO3, lithium metazirconate 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 25 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 54.46% (Li7.78 = 54.46) = 153

                          = 153 = Li2ZrO3 = E = m2c,