ATMOSPHERE OF BERYLLIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Beryllium boride 

        Beryllium = 9-Be  

        Beryllium = 9 

        Beryllium = 4 proton 

        Beryllium = 5 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (5)           +     b2 (4)   

        a2 (25)          + b2 (16) = c2

        a2 + b2 = 41 = c2 

        a2 + b2 = 41 / 9-Be = 4.55

        a2 + b2 = 4.55 = 4 Be proton + H0.55

Beryllium energy atmosphere = 31 % * H0.55 of fusion = 17.05 hour 

                       Because 

                       Hour = 17.05 / 2 proton of He = 8.525-Fluorine  

                            = 8.525 – 4 proton of Be = 4.525-Boron

Fluorine  = 9 proton  

Boron = 5 proton

  Beryllium = 8.525 * 4.525 = 38.575625

            = 38.575625 - 7.575625% (Li + H0.5 = 7.5) = 31

            = 31

 Chemical = 31 - 22 (B2) trivalent metalloid atmosphere of earth = 9

          = 9 = Be = Beryllium 

Chemical formula from 17.05 hours = BeB2  

                                  = BeB2, beryllium boride 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 41 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 268.81% (BeB2) 8.67 = 268.77) = 31

                          = 31 = BeB2 = E = m2c,