ATMOSPHERE OF BERYLLIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Beryllium borohydride 

        Beryllium = 9-Be  

        Beryllium = 9 

        Beryllium = 4 proton 

        Beryllium = 5 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (5)           +     b2 (4)   

        a2 (25)          + b2 (16) = c2

        a2 + b2 = 41 = c2 

        a2 + b2 = 41 / 9-Be = 4.55

        a2 + b2 = 4.55 = 4 Be proton + H0.55

Beryllium energy atmosphere = 36 % * H0.55 of fusion = 19.8 hour 

                       Because 

                       Hour = 19.8 / 2 proton of He = 9.9-Neon  

                            = 9.9 – 4 proton of Be = 5.9-Carbon

Neon  = 10 proton  

Carbon = 6 proton

  Beryllium = 9.9 * 5.9 = 58.41

            = 58.41 - 22.41% (B2 = 22) = 36

            = 36

 Chemical = 36 - 22 (B2) trivalent metalloid atmosphere of earth = 14

          = 14 - 5 (H4) = 9

          = 9 = Be = Beryllium 

Chemical formula from 19.8 hours = Be(BH2)2  

                                 = Be(BH2)2, beryllium borohydride 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 41 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 231.48% (6Be(BH2)2 + HN  = 231.25) = 36

                          = 36 = Be(BH2)2 = E = m2c,