ATMOSPHERE OF BERYLLIUM ON EARTH

ENERGY LAW OF SIKANDER AQEEL = E = m2c 

Beryllium bromide 

        Beryllium = 9-Be  

        Beryllium = 9 

        Beryllium = 4 proton 

        Beryllium = 5 neutron 

        a2 + b2 = c2  

        a2 (neutron)     +     b2 (proton) = c2  

        a2 (5)           +     b2 (4)   

        a2 (25)          + b2 (16) = c2

        a2 + b2 = 41 = c2 

        a2 + b2 = 41 / 9-Be = 4.55

        a2 + b2 = 4.55 = 4 proton + H0.55 

Beryllium energy atmosphere = 169% * H0.55 of fusion = 92.95 hour 

                       Because 

                       Hour = 92.95 / 6 proton of C = 15.49-Sulfur  

                            = 15.49 – 4 proton of Be = 11.49-Magnesium

Sulfur  = 16 proton  

Magnesium = 12 proton

  Beryllium = 15.49 * 11.49 = 177.9801

            = 177.9801 - 8.9801% (9 proton of Fluorine = 9) = 169

            = 169

 Chemical = 169 - 160 (Br2) bromide atmosphere of earth = 9

          = 9 = Be = Beryllium 

Chemical formula from 92.95 hours = BeBr2  

                                  = BeBr2, beryllium bromide 

ENERGY IN ACT BY C1     

Light speed meter seconds = 300000000 / 41 (m2) = 12000000

                          = 12000000 / 24 hour = 500000

                          = 500000 / 60 minute = 8333.33

                          = 8333.33 / 49.3096% (Be4 + CH = 49.25) = 169

                          = 36 = BeBr2 = E = m2c,